The best choice is D prokaryotes dont have a nucleus <span />
Answer:D SEED TREE CUTTING
Explanation:
The answer is seed- tree cutting. Edge2020
It would require that the csf acts exclusively on : Myeloblasts
myeloblasts is a unipotent stem cell, which differentiate into one of the effectors of the granulocyte series.
It is commonly found in bone marrow.
The phosphorylation of fructose 6-phosphate to fructose-1,6-bisphosphate is the committed step in glycolysis because<u> fructose 1,6-bisphosphate can undergo no other reactions than those of glycolysis.</u>
<h3>
What is phosphorylation?</h3>
- The crucial process of glycolysis involves the breakdown of glucose into two molecules of pyruvate. It involves a number of steps and many enzymes.
- It takes place over the course of ten phases, demonstrating how important and crucial phosphorylation is to the production of the final goods. Step 1 of the preliminary step (first half of glycolysis) and step 6 of the payout phase reactions are started by phosphorylation (second phase of glycolysis).
- Because fructose-6-phosphate cannot cross the cell membrane, it is forced to remain inside the cell. Step 3 involves phosphorylation, when fructose-6-phosphate is changed into fructose-1,6-bisphosphate.
To learn more about phosphorylation with the given link
brainly.com/question/15585148
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Answer:
The answer would be D my friend.
Explanation:
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