A fleet of nine taxis is to be dispatched to three airports in such a way that three go to airport A, five go to airport B, and one goes to airport C. In how many distinct ways can this be accomplished?
2.44) Refer to Exercise 2.43. Assume that taxis are allocated to airports at random.
a) If exactly one of the taxis is in need of repair, what is the probability that it is dispatched to airport C?
b) If exactly three of the taxis are in need of repair, what is the probability that every airport receives one of the taxis requiring repairs?
So, my answer to 2.44a is 1/9. Hopefully this is correct at least :)
For 2.44b, my guess was
(3C1)(1/3)(2/3)2 * (5C1)(1/3)(2/3)4 * 1/3
The solutions manual on chegg (which seems to be riddled with errors) says something completely different. Is my calculation correct?
Answer:
Step-by-step explanation:
21/3 = 16/6
126 ≠ 48
does not form a proportion
Answer:
Jewel is 7 years old
John is 1 year old
Dave is 17 years old
Step-by-step explanation:
From the question we are told that:
Jewel age is 
John age 
Dave's age a Year ago

So that Dave.s age this Year could be

Simplifying Equation for Dave's age we have





Dave is 17 years old
Therefore
Johns age is



John is 1 year old
Answer:
See below.
Step-by-step explanation:
Let <em>x</em> represent the number of days.
Since Day and Night Kennel charges a fee of $20 per day and only a one-time fee of $15:

Where <em>y</em> represents the total cost, <em>20x</em> represents the cost for staying <em>x</em> days and <em>15</em> is the initial one-time fee.
For Bark Time Hotel, similarly:

Again, <em>y</em> represents the total cost, <em>30x</em> represents the cost for staying <em>x</em> days, and <em>5</em> is the initial one-time fee.
Thus, the system of equations is:

x-intercept is for y = 0
y-intercept is for x = 0
We have x - 3y = -9.
Put y = 0 to the equation:
x - 3(0) = -9
x - 0 = -9
x = -9
Put x = 0 to the equation:
9 - 3y = -9
-3y = -9 <em>divide both sides by (-3)</em>
y = 3
Answer:
<h3>x-intercept (-9, 0); y-intercept (0, 3)</h3>