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3 years ago

Prove using the notion of without loss of generality that 5x 5y is an odd integer when x and y are integers of opposite parity.

1 answer:

6 0

The expression is
5x + 5y
We are to prove that it is an odd integer when x and y are integers of opposite parity
First, we can assume
x = 2a (even)
y = 2b + 1(odd)
subsituting
10(a + b) + 5
5 [(2(a + b) + 1]
The term
2(a + b) + 1 is odd and the result of an odd number multiplied by an odd number is odd

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Round your answer to the nearest hundredth. ? А C 3 70° B

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It would be 100 degrees

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3 years ago

Really Need Help ! ASAP

SCORPION-xisa [38]

Answer:

hope the above solution will help you

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3 years ago

A company makes wax candles in the shape of a solid sphere. Suppose each candle has a diameter of 15 cm. If

jekas [21]

We have been given that a company makes wax candles in the shape of a solid sphere. Each candle has a diameter of 15 cm. We are asked to find the number of candles that company can make from 70,650 cubic cm of wax.

To solve our given problem, we will divide total volume of wax by volume of one candle.

Volume of each candle will be equal to volume of sphere.

$V=\frac{4}{3}\pi r^3$ , where r represents radius of sphere.

We know that radius is half the diameter, so radius of each candle will be $\frac{15}{2}=7.5$ cm.

$\text{Volume of one candle}=\frac{4}{3}\cdot 3.14\cdot (7.5\text{ cm})^3$

$\text{Volume of one candle}=\frac{4}{3}\cdot 3.14\cdot 421.875\text{ cm}^3$

$\text{Volume of one candle}=1766.25\text{ cm}^3$

Now we will divide 70,650 cubic cm of wax by volume of one candle.

$\text{Number of candles}=\frac{70,650\text{ cm}^3}{1766.25\text{ cm}^3}$

$\text{Number of candles}=\frac{70,650}{1766.25}$

$\text{Number of candles}=40$

Therefore, 40 candles can be made from 70,650 cubic cm of wax.

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3 years ago

A bucket of paint has spilled on a tile floor. The paint flow can be expressed with the function p(t) = 6t, where t represents t

Neko [114]

Answer:

A) A[p(t)] = 36πt²

B) 7234.56 square units

Step-by-step explanation:

Given functions:

$\begin{cases}p(t)=6t \\ A(p)=\pi p^2 \end{cases}$

Part A

To find the area of the circle of spilled paint as a function of time, substitute the function p(t) into the given function A(p):

$\begin{aligned}A(p) & = \pi p^2\\\\ \implies A[p(t)] & = \pi [p(t)]^2\\& = \pi (6t)^2\\& = \pi 6^2 t^2\\& = 36\pi t^2\end{aligned}$

Part B

Given

t = 8 minutes
π = 3.14

Substitute the given values into the equation for A[p(t)} found in part A:

$\begin{aligned}A[p(8)] & = 36\pi t^2\\& = 36 \cdot 3.14 \cdot 8^2\\& = 36 \cdot 3.14 \cdot 64\\& = 113.04 \cdot 64\\& = 7234.56\:\: \sf square\:units\end{aligned}$

Therefore, the area of spilled paint after 8 minutes if 7234.56 square units.

4 0

2 years ago

Read 2 more answers

Need help please!!!!

mario62 [17]

Id say it's choice b top right.

5 0

3 years ago