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lbvjy [14]
3 years ago
13

Which expression represents “one half of x

Mathematics
2 answers:
Lana71 [14]3 years ago
6 0

Answer:

x/2

Hope this helps :)

Korolek [52]3 years ago
5 0
The answer is x/2 goodluck
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E^-2x×(2x – 1)^5 how to derive this plz help​
arlik [135]

Answer:

I put a pic, i hope ill help :)

3 0
3 years ago
PLEASE HELP I WILL MARK BRAINLIEST!!
agasfer [191]
2 times x -4=12
2x-4=12
Let x= 8
(2.8)-4=12
16-4= 12

So the answer is 8
8 0
3 years ago
What second degree polynomial function has a leading coefficient of -2 and root 4 with a multiplicity of 2
OverLord2011 [107]

The second degree polynomial with leading coefficient of -2 and root 4 with multiplicity of 2 is:

p(x) = -2*(x - 4)*(x - 4) = -2*(x - 4)^2

<h3>How to write the polynomial?</h3>

A polynomial of degree N, with the N roots {x₁, ..., xₙ} and a leading coefficient a is written as:

p(x) = a*(x - x_1)*(x - x_2)*...*(x - x_n)

Here we know that the degree is 2, the only root is 4 (with a multiplicity of 2, this is equivalent to say that we have two roots at x = 4) and a leading coefficient equal to -2.

Then this polynomial is equal to:

p(x) = -2*(x - 4)*(x - 4) = -2*(x - 4)^2

If you want to learn more about polynomials:

brainly.com/question/4142886

#SPJ1

8 0
2 years ago
What is F(8) if f(x) = 15x
Lilit [14]

Answer:

F(8)=120

Step-by-step explanation:

f(x)=15x

f(8)=15(8)

f(8)=120

6 0
3 years ago
How do you do this trig problem.
loris [4]

Consider a right triangle in which one of the angles \theta satisfies

\sin\theta=\dfrac35\implies\theta=\sin^{-1}\dfrac35

That is, the side opposite \theta occurs in a ratio of 3 to 5 with the hypotenuse. The side adjacent to \theta then occurs in a ratio of 4 to 5 with the hypotenuse. In other words,

\cos\theta=\dfrac45

because

\sin^2\theta+\cos^2\theta=\dfrac9{25}+\dfrac{16}{25}=1

Then in this triangle,

\cot\theta=\cot\left(\sin^{-1}\dfrac35\right)=\dfrac{\cos\theta}{\sin\theta}=\dfrac{\frac45}{\frac35}=\dfrac43

7 0
3 years ago
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