you will have 10 if im mistaken it is 5 i hope this is kinda helpful im only in 6th grade sorry if it is wrong
I’m really late this time I’m sure you are alr done with your I ready lol
The value of integration of y=16-
from x=-1 to x=1 is 94/3.
Given the equation y=16-
and the limit of the integral be x=-1,x=1.
We are required to find the value of integration of y=16-
from x=-1 to x=1.
Equation is relationship between two or more variables that are expressed in equal to form.Equation of two variables look like ax+by=c.It may be linear equation, quadratic equation, or many more depending on the power of variable.
Integration is basically opposite of differentiation.
y=16-
Find the integration of 16-
.
=16x-
Now find the value of integration from x=-1 to x=1.
=16(1)-
-16(-1)-
=16(1)-1/3+16-1/3
=32-2/3
=(96-2)/3
=94/3
Hence the value of integration of y=16-
from x=-1 to x=1 is 94/3.
Learn more about integration at brainly.com/question/27419605
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Answer: 1. 2rs is 2 . r . s = 2rs 2. 18rst is 2 . 3 . 3 r. s. t = 18rst
3. 25ab is 5 . 5 a . b = 25ab 4. 30abc is 2 . 3 . 5 a . b . c= 30abc 5. 45abr is 3 . 3 . 5 . a . b . r
Step-by-step explanation: 2. 18rst is 2 . 3 . 3 . r . s . t because 2 x 3 = 6 x 3 = 18rst.
3. 25ab is 5 . 5 a . b because 5 x 5 = 25ab
4. 30abc is 2 . 3 . 5 a . b because 2 x 3 = 6 x 5 = 30abc.
5. 45abr is 3 . 3 . 5 . a . b . r because 3 x 3 = 9 x 5 = 45abr.
Hope this works! :) If not, I am sorry :(. If it does, Your Welcome! :)