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2 years ago

9

Paul rides his bike for 2 hours at a constant rate of 20 mph. He then bikes for 3 hours at a constant rate of 25 mph. How far di

d Paul travel in the 5 hours?
A. 15 mi.
B. 52 mi.
C. 115 mi.
D. 165 mi.

1 answer:

Schach [20]2 years ago

4 0

In 5 hours Paul travelled 115 miles

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Answer:

Step-by-step explanation:

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2 years ago

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$\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}$

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<u>Simplifying Rational Expressions</u>

If two or more rational expressions have the same denominator, the add and subtract operations are done only with the numerator. The final denominator will be the common of both.

The expression is:

$\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}$

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$\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-(3q^2-q-6)}{q^2+6q+5}$

Removing parentheses:

$\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-3q^2+q+6}{q^2+6q+5}$

Simplifying:

$\boxed{\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}}$

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