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Natali [406]
3 years ago
9

Who want head...no but frr?​

Mathematics
1 answer:
Vinil7 [7]3 years ago
3 0

Answer:

I’m ok without it

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PLEASE HELP NOBODY EVER ANSWERS MY QUESTIONS Rip van Winkle has fallen asleep for a very long time.
UNO [17]

Answer:

10 millimeters

Step-by-step explanation:

Don't listen to the other answerer who was trolling, I will actually help you. To find how long his beard was when he fell asleep, we need to find the y-intercept. The y-intercept marks how long his beard was right when he fell asleep. From looking at the graph, we can see that the y-intercept is 10. This means his beard was 10 millimeters long when he fell asleep. I hope this helps!

3 0
3 years ago
What is the value of 2x^2 - 4x + 5 when x is -3
IgorLugansk [536]

Answer:

35

Step-by-step explanation:

2x9+12+5=35

4 0
2 years ago
On January 1st Rosie Bank balances was $ 200. During the month, she wrote checks for 115.25 dollars, 315 dollars, and made one d
Firdavs [7]

Answer:

Step-by-step explanation:

$84.75

6 0
3 years ago
Help me with this fast pleaseee
sveta [45]
I’m confused on what it is asking
4 0
3 years ago
Last one lol please help!!!
Mekhanik [1.2K]

Answer:

(C) 50π

Step-by-step explanation:

For this problem, we need to find a way to relate the inner circle, to the square, to the outer circle.

Given that we know the area of a circle is πr^2, and our inner circle has a area of 25π, we can find the radius.

25π = πr^2

25 = r^2

5 = r

Note, that the diameter of the inner circle is parallel to the side of the square, meaning that the diameter of the inner circle is the length of the side of the square.

diameter = 2 * radius

d = 2 * 5 = 10.

Now that we know the value of the side of the square, we can find the length of the diagonal of the square, which is the diameter of the outer circle.

Using the properties of the 45-45-90 right triangle, we can say that the diagonal of the square is the length of the side times sqrt(2).

Outer_Diameter = 10 * sqrt(2)

Now to find the outer area, we need the formula for the area of a circle.  Note that the diameter is twice the radius, so we will simply divide by 2.

A = πr^2

A = π * [ ( 10 * sqrt(2) ) / 2 ]^2

A = π * [ 5 * sqrt(2) ] ^2

A = π * 25 * 2

A = 50π

So the area of the outer circle is 50π.

Cheers.

5 0
3 years ago
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