since its the zeros it should be x -/+ something
(x-1)(x+1)(x+4)
multiply for standard form
((x^2)-1)(x+4)
x^3-x
+ x^2 -4
x^2 + x^2 -x -4
Answer:
12.63
Step-by-step explanation:
First you should draw yourself a square.Since you know it is a square you can find each side by dividing it by 4. 32/4 = 8. Since it is a square you know that both the length and width are 8. If you draw in the diagonal that is a right triangle. Use the Pythagorean theorem a^2 + b^2= c^2 to find the length of the diagonal.
8^2 + 8^2 = c^2
There is no slope, it’s undefined. you get this by doing 9-(-4)/-4-(-4). this comes out to 13/0, and anything over zero is undefined. hope this helped
Answer:
A and D both equations don't have any solution
Step-by-step explanation:
y = 3x + 2
so y ≠ - 3x - 2
if 3x + y = 8
then 3x + y ≠ 9
