3 years ago

What is the x integer for the equation y=3x- 2

Mathematics

1 answer:

Aleksandr [31]3 years ago

8 0

Answer:

maybe x=0=>y=1 or maybe x=0=>y=-2

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How do i determine the domain and the equation of the vertical asymptote of the equation f(x)=ln (x+2)-1?

svetlana [45]

If I am reading the equation correctly, I do not believe it has a solution.

3 0

3 years ago

Pru, Piper, and Phoebe share apples in the ratio 5:3:4. If Pru has 24 more apples than Piper, how many apples does Phoebe have?

Bezzdna [24]

Answer: Phoebe have 48 apples.

Explanation:

It is given that Pru, Piper, and Phoebe share apples in the ratio 5:3:4. If Pru has 24 more apples than Piper.

Let the total number of apples be x.

The sum of the ratios is,

$Sum=5+3+4=12$

Therefore the number of apples shared by Pru, Piper, Phoebe are $\frac{5}{12}x, \frac{3}{12}x,\frac{4}{12}x$ respectively.

It is given that Pru has 24 more apples than Piper, so

$\frac{5}{12}x-\frac{3}{12}x=24$

$\frac{5-3}{12}x=24$

$\frac{2}{12}x=24$

$\frac{1}{6}x=24$

$x=144$

Since phoebe have $\frac{4}{12}x$ appels,

$\frac{4}{12}x=\frac{4}{12}\times 144=48$

Therefore, Phoebe have 48 apples.

8 0

3 years ago

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Help if you answer I’ll mark you brainliest

Delicious77 [7]

Answer:

I CAN'T SEE ANYTHING FROM THAT FAR SORRY BUT I WISH I COULD HELP YOU!!!

Step-by-step explanation:

(again sorry)!

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3 years ago

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(I have a deadline in 3 hours :c ) Ann's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs

max2010maxim [7]

A=3B
4.35A+5.40B=780.95
Substitute 3B into A for the second equation:
4.35(3B)+5.40B=780.90
13.05B+5.40B=780.90
18.45B=780.90
B=42.33
Plug into equation 1:
A=3B
A=3(42.33)
A=126.98

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4 years ago

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The ages of three children in a family can be expressed as consecutive integers. The square of the age of the youngest child is

tensa zangetsu [6.8K]

Answer: 10, 11, & 12

<u>Step-by-step explanation:</u>

Let x represent the age of the youngest child.

Their ages are consecutive so,

Youngest: x

Middle: x + 1

Oldest: x + 2

The age of the Youngest squared (x²) equals 8 times the Oldest [8(x + 2)] plus 4.

x² = 8(x + 2) + 4

x² = 8x + 16 + 4

x² = 8x + 20

x² - 8x - 20 = 0

(x - 10)(x + 2) = 0

x - 10 = 0 or x + 2 = 0

x = 10 or x = -2

Since age cannot be negative, x = -2 is not valid

So, the Youngest (x) is 10

the Middle (x + 1) is 11

and the Oldest (x + 2) is 12

4 0

3 years ago