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yulyashka [42]
2 years ago
6

3x+7=7x+8-3x how do i solve this? is it like infinite solutions, no solutions (Ø) or an actual number answer?

Mathematics
2 answers:
oksano4ka [1.4K]2 years ago
8 0

Answer:

x=-1

Step-by-step explanation:

3x+7=7x+8-3x

3x+7=4x+8

-4x      -4x

-x+7=8

   -7  -7

<u>-x=1</u>

 -1

x=-1

Savatey [412]2 years ago
4 0

Hey there!

3x + 7 = 7x + 8 - 3x

3x + 7 = 4x + 8

SUBTRACT 4x to BOTH SIDES

3x + 7 - 4x = 4x + 8 - 4x

WORK IT OUT!

NEW EQUATION: -x + 7 = 8

-1x + 7 = 8

SUBTRACT 7 to BOTH SIDES

-1x + 7 - 7 = 8 - 7

CANCEL out: 7 - 7 because it give you 0

KEEP: 8 - 7 because it give you the value of x.

NEW EQUATION: -1x = 8 - 7

SIMPLIFY IT!

-1x = 1

DIVIDE -1 to BOTH SIDES

-1x/-1 = 1/-1

CANCEL out: -1/-1 because it give you 1

KEEP: 1/-1 because it give you the value of x

NEW EQUATION: x = 1/-1

SIMPLIFY IT!

x = -1

Therefore, your answer is: x = -1

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

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Sladkaya [172]

Answer:

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For each driver stopped for speeding, there are only two possible outcomes. Either they have invalid licenses, or they do not. The probability of a driver having an invalid license is independent from other drivers. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

13 percent of the drivers stopped for speeding have invalid licenses.

This means that p = 0.13

14 drivers are stopped

This means that n = 14

(a) None will have an invalid license.

This is P(X = 0)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{14,0}.(0.13)^{0}.(0.87)^{14} = 0.1423

(b) Exactly one will have an invalid license.

This is P(X = 1)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{14,1}.(0.13)^{1}.(0.87)^{13} = 0.2977

(c) At least 2 will have invalid licenses.

Either less than 2 have invalid licenses, or at least 2 does. The sum of the probabilities of these events is decimal 1. Mathematically, this is

P(X < 2) + P(X \geq 2) = 1

We want P(X \geq 2)

So

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In which

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P(X \geq 2) = 1 - P(X < 2) = 1 - 0.44 = 0.56

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Step-by-step explanation:

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