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REY [17]
3 years ago
7

What is the angular position in radians of the minute hand of a clock at 2:55?

Physics
2 answers:
OleMash [197]3 years ago
8 0
Refer to the diagram shown.

There are twelve 5-minute divisions.
Each 5-minute division is equal to 360°/12 = 30°.

By convention, angles are measured counterclockwise from the positive x-axis.
The angular position of the minute hand at 2:55 is
θ = 90° + 30° = 120°

Because 360° = 2π radians, therefore
θ = (120/360)*2π = (2π)/3 radians  = 2.0944 radians

Answer: (2π)/3 radians ofr 2.0944 radians.

Licemer1 [7]3 years ago
6 0
<span>(2pie radian/12) *11= 5.7566 radian</span>
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An airplane travels 4000m in 16 seconds on a heading of 35 whats is its velocity
Marizza181 [45]

In the question, you just gave a complete and detailed
description of the plane's velocity vector:

       4,000/16  meters/second , heading 35 degrees .

You might want to simplify the speed and make it a unit rate,
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         250 meters/second, heading 35 degrees .

6 0
3 years ago
How does friction make it possible for you to walk across the floor?
Tema [17]

if we are walking on a perfectly smooth ground which has no friction our force would simply cancel out the force reverted by the ground and we would fall.

We need it to help push out feet off the ground

Hope those helps :)

5 0
3 years ago
The accompanying table shows measurements of the Hall voltage and corresponding magnetic field for a probe used to measure magne
aalyn [17]

0.125 mm . is the thickness of the sample.

<h3>What do you mean by hall voltage ?</h3>

The Hall effect is the creation of a voltage difference (the Hall voltage) across an electrical conductor, which is transverse to an applied magnetic field perpendicular to the current and an electric current in the conductor. Edwin Hall made the discovery in 1879.

We need to know the material's current, magnetic field, length, number of charge carriers, and area in order to calculate the Hall voltage. The Hall voltage is computed using the formula: v=IBlneA=(100A)(1.5T)(1.0102m)(5.91028/m3)(1.61019C)(2.0105m2)=7.9106V.

lof4

First we have to plot those point Then we can use some computer program to fit those point linearly to get slope

of that graph a and interception b. We already know, from theory, that Hall's voltage AVH and magnitude of

magnetic field B are connected as

ΔV_{H} =\frac{I}{nqt} B

where I is current trough probe, n is concentration of charge carriers, q = 1.6 • 10¯19 C is charge of charge

carries and t is thickness of the material. We have put the data from the problem on a graph and fitted linearly and

got

a = 100 μ\frac{V}{T}

b = —0.02  μV.

As we can see, our result are in agreement with theoretical assumptions because interception b is almost O, and a

is asked relation between Hall's voltage A VH and magnitude of magnetic field B. Then we can write

ΔVH =100X10^{-6} V/TB

(4) Then we can use result (4) and numbers from the textbook to calculate the thickness of the sample as

a=\frac{I}{nqt} \\t=\frac{I}{anq} \\t=\frac{.200A}{100X10^{-6}X 1.6 X10^{-19}X10^{26}  } \\t=0.125mm

To learn more about the hall voltage , Visit: brainly.com/question/19130911

#SPJ4

8 0
2 years ago
A rocket for use in deep space is to have the capability of boosting a total load (payload plus the rocket frame and engine) of
choli [55]

Answer:

<em>13.54 tons</em>

Explanation:

Let f be the amount of fuel oxidizer needed

v be the speed

The relationship between them is inverse in nature i.e

f ∝ 1/v

f = k/v

If a rocket for use in deep space is to have the capability of boosting a total load (payload plus the rocket frame and engine) of 3.25 metric tons to a speed of 10,000 m/s, then f = 3.25 when v  = 10,000

Substitute and get k

k = fv

k = 3.25 * 10,000

k = 32500

To get the amount of fuel oxidizer required to produce a speed of 2400m/s, we will find f when v = 2400m/s

Recall that f = k/v

f = 32500/2400

f = 13.54 metric tons

<em>Hence the fuel plus oxidizer that will be required is 13.54 tons</em>

4 0
3 years ago
A sound wave will rebound when it encounters what?
Over [174]
The sound wave will rebound when it is a barrier, hope this helps
8 0
3 years ago
Read 2 more answers
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