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sattari [20]
3 years ago
14

As you jump on a pogo stick where is the potential energy the greatest?

Physics
1 answer:
slamgirl [31]3 years ago
7 0
The potential energy would be greatest at the highest point of the jump; the kinetic energy equaling 0.
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A body of mass 10kg has a height of 200cm, calculate the potential energy. (Take g =
Nastasia [14]

The potential energy of the body is "200 Joule".

According to the question,

Mass,

  • m = 10 kg

Height,

  • h = 200 cm

or,

           = 2 m

  • g = 10 m/s⁻¹

As we know,

→ The potential energy will be:

= mgh

By putting the given values, we get

= 10\times 10\times 2

= 200 \ Joule

Thus the above answer is right.

Learn more about potential energy here:

brainly.com/question/23859978

5 0
3 years ago
Read 2 more answers
Ten seconds after an electric fan is turned on, the fan rotates at 300 rev/min. its average angular acceleration is
Tcecarenko [31]
Check the attached file for the answer.

6 0
3 years ago
Using the projectiles equations for y and x at what second does the ball have a vertical velocity of -39.2 m/s^2
vovangra [49]

Answer:

<h2>a) t = 4</h2>

Explanation:

In projectile the time taken by an object to reach its maximum height is the maximum time (tmax).

tmax = Usin\theta/g

U = velocity of the ball

\theta = angle of projection = 90° (vertical velocity)

g = acceleration due to gravity = 9.8m/s²

tmax = Usin90°/9.8

tmax = U/9.8

T the maximum height U = Uy =  39.2 m/s²

tmax = 39.2/9.8

tmax = 4secs

To calculate the time at which the ball will have an horizontal velocity, we will use the same formula but \theta will be 0° in this case

If Ux = Ucos\theta

8 = Ucos0

U = 8m/s

Since t = Usin\theta/g

t = 8sin0/9.8

t = 0sec

8 0
3 years ago
If 4000 C of charge pass through a section of wire in 50 seconds, what would the current be?
9966 [12]

Answer:

Explanation:

Given that,

Charge through a wire is

Q = 4000C

Time for charge to pass through the wire is

t = 50seconds

Then,

Current through the wire is the rate of charge passing through the wire

Q = it

Where

Q is charge.

I is current

t is time taken

Therefore,

I = Q / t

I = 4000 / 50

I = 80 Amps

3 0
4 years ago
Chanice drives her scooter 7 kilometers north. she stops for lunch and then drives 5 kilometers and then 1 km east again. what d
lord [1]

Distance covered is given as follows

1). 7 km North

2). 5 km North

3). 1 km East

Now total distance covered will be given as

d = d_1 + d_2 + d_3

d = 7 km + 5 km + 1 km

d = 13 km

Now in order to find the displacement we will show all with their directions

\vec d_1 = 7 + 5 = 12 km towards North

\vec d_2 = 1 km towards East

So total displacement is

\vec d = \vec d_1 + \vec d_2

\vec d = 12 \hat j + 1 \hat i

so net displacement will be

d = \sqrt{12^2 + 1^2} = 12.04 km

so displacement is 12.04 km

6 0
4 years ago
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