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sattari [20]
3 years ago
14

As you jump on a pogo stick where is the potential energy the greatest?

Physics
1 answer:
slamgirl [31]3 years ago
7 0
The potential energy would be greatest at the highest point of the jump; the kinetic energy equaling 0.
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(c) the fraction of energy lost during the impact

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What a brief summary about why taking Athletics is important.
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Physical education is a component of education that challenges students by providing opportunities to attain the skills and knowledge to be physically active as part of a healthy lifestyle. Demonstrates a variety of physical skills through movement activities.

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Two waves can share the same space and pass through one another. What type of interference occurs when the crests of one wave ov
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Question 25 Answer: Destructive interference occurs.

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4 0
3 years ago
a. A beam of light is incident from air on the surface of a liquid. If the angle of incidence is 26.7° and the angle of refracti
Diano4ka-milaya [45]

Answer:

(a). The critical angle for the liquid when surrounded by air is 44.37°

(b). The angle of refraction is 26.17°.

Explanation:

Given that,

Incidence angle = 26.7°

Refraction angle = 18.3°

(a). We need to calculate the refraction of liquid

Using Snell's law

n=\dfrac{\sin i}{\sin r}

Put the value into the formula

n=\dfrac{\sin 26.7}{\sin 18.3}

n=1.43

We need to critical angle for the liquid when surrounded by air

Using formula of critical angle

C=\sin^{-1}(\dfrac{1}{n})

Put the value into the formula

C=\sin^{-1}(\dfrac{1}{1.43})

C=44.37^{\circ}

(b). Given that,

Incidence angle = 37.5°

Speed of light in mineral v=2.17\times10^{8}\ m/s

We need to calculate the index of refraction

Using formula of index of refraction

n=\dfrac{c}{v}

Put the value into the formula

n=\dfrac{3\times10^{8}}{2.17\times10^{8}}

n=1.38

We need to calculate the angle of refraction

Using Snell's law

n=\dfrac{\sin i}{\sin r}

\sin r=\dfrac{\sin i}{n}

Put the value into the formula

\sin r=\dfrac{\sin 37.5}{1.38}

r=\sin^{-1}(\dfrac{\sin 37.5}{1.38})

r=26.17^{\circ}

Hence, (a). The critical angle for the liquid when surrounded by air is 44.37°

(b). The angle of refraction is 26.17°.

3 0
3 years ago
Read 2 more answers
A machinist with normal vision has a near point at 25 cm. The machinist wears eyeglasses in order to do close work. The power of
Alik [6]

Answer:

17.4 cm

Explanation:

Power of lens = +1.75 diopters

Focal length of lens

f=\frac{100}{1.75}=\frac{400}{7}

This is a convex lens as focal the diopter given is positive which makes the focal length positive. Image distance will be negative.

v = -25

\frac{1}{v}-\frac{1}{u}=\frac{1}{f}\\\Rightarrow \frac{1}{-25}-\frac{1}{u}=\frac{1}{\frac{400}{7}}\\\Rightarrow -\frac{1}{u}=\frac{7}{400}+\frac{1}{25}\\\Rightarrow \frac{1}{u}=-\frac{7}{400}-\frac{1}{25}\\\Rightarrow \frac{1}{u}=-0.0575\\\Rightarrow u=-17.4\ cm

∴ The new near point is 17.4 cm

7 0
3 years ago
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