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2 years ago

HELP?????PLEASE?????

Mathematics

1 answer:

irga5000 [103]2 years ago

4 0

9514 1404 393

Answer:

(a) and (b) or (b) and (a) or (c) and (d)

Step-by-step explanation:

The point about which the rotation occurs will remain in place, so the translation that happens after must move it to its corresponding location in the other triangle.

There are three possible correct answers:

180° about point E; right 3 and down 4 . . . (a) and (b)
180° about point G; left 3 and up 4 . . . (b) and (a)
180° about point H; right 5 and up 2 . . . (c) and (d)

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2 years ago

What is the remainder of (4x2 + 7x-1)= (4 + x)? A. -9x – 1 B.23x – 1 C.35 D.-37

bearhunter [10]

Answer: I don't know what you meant by remainder but i hope this helps :)

$x=\frac{-3+\sqrt{29}}{4},\:x=-\frac{3+\sqrt{29}}{4}\\$

Step-by-step explanation:

$\left(4x^2+7x-1\right)=\left(4+x\right)\\\mathrm{Refine}\\4x^2+7x-1=4+x\\\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}\\4x^2+7x-1-x=4+x-x\\Simplify\\4x^2+6x-1=4\\\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}\\4x^2+6x-1-4=4-4\\\mathrm{Simplify}\\4x^2+6x-5=0\\\mathrm{For\:}\quad a=4,\:b=6,\:c=-5:\\\quad x_{1,\:2}=\frac{-6\pm \sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}$

$\frac{-6+\sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}\\=\frac{-6+\sqrt{6^2+4\times \:4\times \:5}}{2\times \:4}\\=\frac{-6+\sqrt{116}}{2\times \:4}\\=\frac{-6+\sqrt{116}}{8}\\\\Let\: simplify\: ; -6+2\sqrt{29}\\=-2\times \:3+2\sqrt{29}\\=2\left(-3+\sqrt{29}\right)\\=\frac{2\left(-3+\sqrt{29}\right)}{8}\\=\frac{-3+\sqrt{29}}{4}\\$

$\frac{-6-\sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}\\\\=\frac{-6-\sqrt{6^2+4\times \:4\times \:5}}{2\times \:4}\\\\=\frac{-6-\sqrt{116}}{2\times \:4}\\\\=\frac{-6-2\sqrt{29}}{8}\\\\=-\frac{2\left(3+\sqrt{29}\right)}{8}\\\\=-\frac{3+\sqrt{29}}{4}\\\\\\x=\frac{-3+\sqrt{29}}{4},\:x=-\frac{3+\sqrt{29}}{4}$

6 0

2 years ago

Read 2 more answers

Pls help me first get 10 you know

Luba_88 [7]

Option D, 63 cm

Explanation:

The scale of model is of local park is

This means that each dimension of the model is 21 times smaller than the actual park (to be developed in future)

Given -

Depth of the pond centi meter

Depth of the real pond will be 21 times of the depth of the model.

Thus , real pond's depth is equal to

Hence, option D is correct

7 0

2 years ago