Let
x--------> the number
we know that
11²=121
12²=144
then
x² must be greater than 121 and less than 144
case a) <span>√115
if x=</span><span>√115
then
x</span>²=115-------> is not greater than 121
case b) <span>√121
</span>if x=√121
then
x²=121-------> is not greater than 121
case c) <span>√136
</span>if x=√136
then
x²=136-------> is greater than 121 and is less than 144------> is ok
case d) <span>√150
</span>if x=√150
then
x²=150------> is not less than 144
therefore
the answer is
√136
To make it easier just assume there is no decimal point then just work out the 32÷4 where we know that 4 goes into 32 8 times so you get 8 remember the decimal point and since it was one decimal place you will push the decimal over to the left of 8 and that is how you get 0.8
Answer:
46 cm
Step-by-step explanation:
Let p represent the length in cm of 1 bap'ai; let k represent the length in cm of 1 bok'ai. Then we have ...
12p +2k = 100
10p +10k = 100
Subtracting the second equation from 5 times the first, we get ...
5(12p +2k) -(10p +10k) = 5(100) -(100)
50p = 400
p = 8 . . . . cm
Then the second equation tells us ...
10(8) +10k = 100
10k = 20
k = 2 . . . . cm
Then 5p+3k = 5(8) +3(2) = 46 cm.
The distance 5 bap'ai and 3 bok'ai is 46 cm.
Answer:
v=πr^2h
v/πr^2=h
Step-by-step explanation:
The value of x is 2. hope it helps!
