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3 years ago

you find a jacket whose price is $117.95 which is on sale with a 30% discount. what is the sale price?

Mathematics

2 answers:

Radda [10]3 years ago

3 0

Answer:

Discount: $47.99 the 30 % off

Sale Price: $111.99 the final price

hope this helps

Step-by-step explanation:

Burka [1]3 years ago

3 0

Answer:

The sale price is about $82.57.

Step-by-step explanation:

$117.95/100=$1.1795

$1.1795*70=$82.565

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frosja888 [35]

Answer

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Step-by-step explanation:

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2 years ago

Pls help with Question 11.<br> I need to submit it by tmr

Wewaii [24]

Answer: 81.85 km/hr

Converting m/sec into km/hr, 25 m/sec = 90 km/hr

Average =

Time = 50/90 = 5/9 hr

next 120 km at an average speed of 80km/h

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last part of its journey at an average speed of 90km/h in 35 Minutes

time = 35 minutes = 35/60 hr = 7/12 hr

Distance covered = 90 * 7 /12 = 105/2 km

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3 years ago

X/8 - I/2 = 6 what is the answer to x

notka56 [123]

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3 years ago

The domain of the following relation: R: {(−3, 4), (5, 0), (1, 5), (2, 8), (5, 10)} is:

Shalnov [3]

Answer:

For an ordered pair (x,y) that a set contain :

x = Domain of the relation

y = Range of the relation

In a relation x can have two or more than two ranges i.e a x can have more or more than two images.

So, Domain = First element of ordered pair that the following relation R contains ={(−3, 4), (5, 0), (1, 5), (2, 8), (5, 10)}= -3, 5, 1,2,5

But the element 5 is Occuring twice.

Domain = { -3,1,2,5} →→Option A

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3 years ago

Read 2 more answers

Find the components of the vertical force Bold Upper Fequalsleft angle 0 comma negative 8 right anglein the directions parallel

nydimaria [60]

Answer with Step-by-step explanation:

We are given that

F=<0,-8>=0i-8j=-8j

$\theta=\frac{\pi}{3}$

The component of force is divided into two direction

1.Along the plane

2.Perpendicular to the plane

1.The vector parallel to the plane will be= $r=cos\frac{\pi}{3}i-sin\frac{\pi}{3}j=\frac{1}{2}i-\frac{\sqrt 3}{2}j$

By using $cos\frac{\pi}{3}=\frac{1}{2},sin\frac{\pi}{3}=\frac{\sqrt 3}{2}$

Force along the plane will be= $\mid F_x\mid=F\cdot r$

Force along the plane will be = $\mid F_x\mid=F\cdot (\frac{1}{2}i-\frac{\sqrt 3}{2}j)=-8j\cdot(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=8\times \frac{\sqrt 3}{2}=4\sqrt 3$ N

By using $i\cdot i=j\cdoty j=k\cdot k=1,i\cdot j=j\cdot k=k\cdot i=j\cdot i=k\cdot j=i\cdot k=0$

Therefore, force along the plane= $\mid F_x\mid(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)$

2.The vector perpendicular to the plane= $r=-sin\frac{\pi}{3}-cos\frac{\pi}{3}=-\frac{\sqrt 3}{2}i-\frac{1}{2}j$

The force perpendicular to the plane= $\mid F_y\mid=F\cdot r=-8j(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)$

The force perpendicular to the plane= $4$ N

Therefore, $F_y=4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)$

Sum of two component of force= $F_x+F_y=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)+4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)$

Sum of two component of force= $2\sqrt 3i-6j-2\sqrt3 i-2j=-8j$

Hence,sum of two component of forces=Total force.

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3 years ago