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saul85 [17]
3 years ago
15

Assume that the following confidence interval for the difference in the mean length of male​ (sample 1) and female babies​ (samp

le 2) at birth was constructed using independent simple random samples. What does the confidence interval suggest about the difference in length between male babies and female​ babies? minus −0.2 in. less than < mu 1 μ1 minus − mu 2 μ2 less than <1.7 in.a female babies are longer
b male babies are longer
c there is no difference in the length between male and female babies
Mathematics
1 answer:
Maksim231197 [3]3 years ago
5 0

Answer:

c. There is no difference in the length between male and female babies

Step-by-step explanation:

Hello!

If I understood correctly, the interval [-0.2;1.7] was constructed to estimate the difference between the population mean of the length of male babies at birth(μ₁) and the population mean of the length of female babies at birth (μ₂).

Estimated parameter: μ₁-μ₂

To make a desition using an interval your hypothesis must be two-tailed,

H₀: μ₁-μ₂ = 0

H₁: μ₁-μ₂ ≠ 0

The level of significance should be complementary to the confidence level of the interval. (For example, if the interval was constructed at 1 - α: 0.9, the test should have a level of α: 0.10)

Remember the Confidence interval is an estimation of the real value of μ₁-μ₂, so, under the null hypothesis you can say that:

If the interval contains the 0, then you don't reject the null hypothesis.

If the interval doesn't contain the 0, you reject the null hypothesis.

So since 0 is contained in the confidence interval, you support the null hypothesis, in other words, there is enough information to say that there is no difference between the average length of male and female babies at birth.

I hope it helps!

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monitta

Answer:

<em>Proof below</em>

Step-by-step explanation:

<u>Right Triangles</u>

In any right triangle, i.e., where one of its internal angles is 90°, some interesting relations stand. One of the most-used is Pythagora's Theorem.

In a right triangle with shorter sides a and b, and longest side c, called the hypotenuse, the following equation is satisfied:

c^2=a^2+b^2

The image provided in the question shows a line passing through points A(0,4) and B(3,0) that forms a right triangle with both axes.

The origin is marked as C(0,0) and the point M is the midpoint of the segment AB. We have to prove.

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First, find the coordinates of the midpoint M(xm,ym):

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Step-by-step explanation:

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Please help me if you can. please show how you got the answer.
fomenos

Answer:

Step-by-step explanation:

The area of a circle is A = πr², where r is the radius. That means in order to solve this we have to find the value of x, which is the diameter of the lake, and then divide it in half to get the radius. To find x we will use similar triangles and proportions. x is the height of the big triangle and 4.5 is the height of the smaller triangle; 15.3 + 7.4 is the hypotenuse of the big triangle and 7.4 is the hypotenuse of the smaller triangle. Setting up our proportion:

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The length of BC is 4 \sqrt{5}.

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<u>Leg rule of geometric mean theorem:</u>

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Taking square root on both sides.

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square and square roots get canceled, we get

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