Answer:
D.
Step-by-step explanation:
Alright my friend so if she ran 1/4 a mile in just 3 minutes then her overall time will be 12 minutes because she still has 3 more to go so basically it'll be 3 x 4 = 12
Hi!
To compare this two sets of data, you need to use a t-student test:
You have the following data:
-Monday n1=16; <span>x̄1=59,4 mph; s1=3,7 mph
-Wednesday n2=20; </span>x̄2=56,3 mph; s2=4,4 mph
You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.

To calculate the degrees of freedom you need to use the following equation:

≈34
The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10
So, as the calculated value is higher than the critical tabulated one,
we can conclude that the average speed for all vehicles was higher on Monday than on Wednesday.
Answer: 
<u>Step-by-step explanation:</u>
Average rate of change is the slope (m) between the two coordinates (-1, -1) and (1, -2).



Answer:
i dont know can you turn your sceen so i can see it better
Step-by-step explanation: