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3 years ago

Distributive/ like terms Pre-Alegbra Overdue!!

Mathematics

2 answers:

Fed [463]3 years ago

7 0

Answer is going to 9

il63 [147K]3 years ago

3 0

HI!

Here are the answers:

1) x=39/7 or 5.57

2) x=1

3) y=42

4) c=9

I hope this helps!

Feel free to mark brainliest!

If you have any other questions, don't hesitate to let me know!

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HURRY PLEASE

Sauron [17]

Answer:

gallons of punch in all = 4.5 gallons

Step-by-step explanation:

Morgan poured 3/4 gallons of punch into each of 6 bottles . This means Morgan poured 3/4 gallons of punch in each of the available 6 bottle .

He pours 3/4 gallons of punch in 1 bottle . For 6 bottles the gallons of punch poured is calculated below

1 bottle = 3/4 gallons of punch

6 bottles = ? gallons of punch

cross multiply

gallons of punch in all = 3/4 × 6

gallons of punch in all = 18/4

gallons of punch in all = 9/2 gallons

gallons of punch in all = 4.5 gallons

5 0

3 years ago

8142÷22=?Write your answer as a whole number and remainder.

White raven [17]

The answer would be 370 2/22.

This is also equivalent to 370 1/11.

Hope this helps. If you have any questions, place it in the comment section below.

5 0

4 years ago

Read 2 more answers

What is 0.22222222 in bar notation

dsp73

Answer: Hello, Maybe this can help you figure out it This is called bar notation. Bar notation is an easier way to write a repeating number by putting a line, or bar, over the repeating numbers. But using bar notation, you would say 1 / 7 = 0.142857 with a line over those numbers to show that they repeat over and over.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

One method of slowing the growth of an insect population without using pesticides is to introduce into the population a number o

Zielflug [23.3K]

To be clear, the given relation between time and female population is an integral:
 $t = \int { \frac{P+S}{P[(r - 1)P - S]} } \,
dP$

The problem says that r = 1.2 and S = 400, therefore substituting:
 $t = \int { \frac{P+400}{P[(1.2 - 1)P - 400]}
} \, dP$ 

= $
\int { \frac{P+400}{P(0.2P - 400)} } \, dP$

In order to evaluate this integral, we need to write this rational function in a simpler way:
 $\frac{P+400}{P(0.2P - 400)} = \frac{A}{P} +
\frac{B}{(0.2P - 400)}$ 

where we need to evaluate A and B. In order to do so, let's calculate the LCD:
 $\frac{P+400}{P(0.2P - 400)} = \frac{A(0.2P -
400)}{P(0.2P - 400)} + \frac{BP}{P(0.2P - 400)}$ 

the denominators cancel out and we get:
P + 400 = 0.2AP - 400A + BP
 = P(0.2A + B) - 400A

The two sides must be equal to each other, bringing the system:
 $\left \{ {{0.2A + B = 1} \atop {-400A =
400}} \right.$ 

Which can be easily solved:
 $\left \{ {{B=1.2} \atop {A=-1}} \right.$ 

Therefore, our integral can be written as:
 $t = \int { \frac{P+400}{P(0.2P - 400)} } \,
dP = \int {( \frac{-1}{P} + \frac{1.2}{0.2P-400} )} \, dP$ 
= $- \int { \frac{1}{P} \, dP +
1.2\int { \frac{1}{0.2P-400} } \, dP$ 
= $- \int { \frac{1}{P} \, dP +
6\int { \frac{0.2}{0.2P-400} } \, dP$ 
= - ln |P| + 6 ln |0.2P - 400| + C

Now, let’s evaluate C by considering that at t = 0 P = 10000:
0 = - ln |10000| + 6 ln |0.2(10000) - 400| + C
C = ln |10000| - 6 ln |1600|
C = ln (10⁴) - 6 ln (2⁶·5²)
C = 4 ln (10) - 36 ln (2) - 12 ln (5) 
 Therefore, the equation relating female population with time requested is:
t = - ln |P| + 6 ln |0.2P - 400| + 4 ln (10) - 36 ln (2) - 12 ln (5)

8 0

3 years ago

Does this graph show a function. Explain

Ira Lisetskai [31]

Yes, the line passes the vertical line test (no x-values are repeated)

8 0

3 years ago

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