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3 years ago

1. The molecular mass of hydrochloric acid (HCI) is 36.5 g/mol. How many moles of HCl are in 120g of HCI?

Chemistry

1 answer:

salantis [7]3 years ago

8 0

Answer:

3.3 mol HCl

General Formulas and Concepts:

Chemistry - Atomic Structure

Using Dimensional Analysis

Explanation:

Step 1: Define

120 g HCl

Step 2: Identify Conversions

Molar Mass of HCl - 36.5 g/mol

Step 3: Convert

$120 \ g \ HCl(\frac{1 \ mol \ HCl}{36.5 \ g \ HCl} )$ = 3.28767 mol HCl

Step 4: Check

We are given 2 sig figs as our lowest. Follow sig fig rules and round.

3.28767 mol HCl ≈ 3.3 mol HCl

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3 years ago

Sodium hydroxide reacts with carbondioxide as follows: 2 naoh(s) + co2 (g) → na2co3 (s) + h2o(l) which reagent is the limiting r

tensa zangetsu [6.8K]

1) Balanced chemical equation:

2 NaOH(s) + CO₂ (g) → Na₂CO₃ (s) + H₂O (l)

2) Mole ratio

2 mole NaOH : 1 mol CO₂ : 1 mol Na₂CO₃ : 1 mol H₂O

3) Limiting reactant

1.85 mol NaOH / 1.00 mol CO₂ < 2 mole NaOH / 1 mol CO₂ ⇒ NaOH is not enough to react with 1.00 mole of CO₂ (more NaOH is needed), so NaOH is the limiting reactant.

Answer: the limiting reactant is NaOH

4) How many moles of sodium carbonate can be produced?

Set the proportion relation using the limiting reactant (the one that reacts completely) and the theoretical mole ratio.

2 mole NaOH / 1mol Na₂CO₃ = 1.85 mol NaOH / x

x = 0.925 mol Na₂CO₃

Answer: 0.925 moles Na₂CO₃

5) How many moles of the excess reactant remain after the completion of the reaction?

The excess reactant is CO₂.

The amount of CO₂ consumed is calculated with a proportion:

2 mol NaOH / 1 mol CO₂ = 1.85 mol NaOH / x

⇒ x = 1.85 / 2 = 0.925mol CO₂

The amount remaining is the original amount less the amount that reacted = 1 mol - 0.925 mol = 0.075 mol.

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3 years ago

Drag each label to the correct location on the table.

AleksAgata [21]

Explanation:

1) Boyle's Law: This law states that pressure is inversely related to the volume occupied by the gas at constant temperature and number of moles.

$P\propto \frac{1}{V}$ (At constant temperature and number of moles)

When the size of the chamber is increased the volume occupied the gas will increase with which pressure exerted by the gas will decrease down.
When we press the inflated balloon the pressure on the gas is increased with which volume of the occupied by the gas inside the balloon decreased.

2) Charles' Law: This law states that volume occupied by the gas is directly related to the temperature of the gas at constant pressure and number of moles.

$V\propto T$ (At constant pressure and number of moles)

The size of the balloon deceases because the in winters the temperature decreases with which volume of the gas present in the balloon also decreases.
When the flexible closed container is heated the temperature of the gas inside the container increases with which the volume occupied by the gas in the container will increase resulting in expanding of container.

3) Avogadro's Law: This law states that volume occupied by the gas is directly related to the number of moles of the gas at constant pressure and temperature.

$V\propto n$ (At constant temperature and pressure)

When we blow air into the balloon the umber of air particles increases with which the volume of the gas inside the balloon also increases resulting in increase in size of the balloon.

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3 years ago

Convert to moles: 100.0g Ca3(PO4)2

salantis [7]

Answer:

0.322 moles

Explanation:

Given Mass, m = 100 g

The molar mass of Ca₃(PO₄)₂

Ca₃(PO₄)₂ = (3 x 40.08) + (2 x 30.97) + (8 x 16.00)

M = 310.18 g/mol

Let there are n number of moles,

n = given mass/ molar mass

$n=\dfrac{100 }{310.18 }\\\\n=0.322\ mol$

So, there are 0.322 moles.

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3 years ago

1. The molecular mass of hydrochloric acid (HCI) is 36.5 g/mol. How many moles of HCl are in 120g of HCI? ​

1. The molecular mass of hydrochloric acid (HCI) is 36.5 g/mol. How many moles of HCl are in 120g of HCI?