Compound A and compound B are constitutional isomers with molecular formula C3H7Cl. When compound A is treated with sodium metho
1 answer:
Answer:
Compound A and compound B are constitutional isomers with molecular formula C3H7Cl.
When compound A is treated with sodium methoxide, a substitution reaction predominates. When compound B is treated with sodium methoxide, an elimination reaction predominates.
Explanation:
Constitutional isomers are the one which differs in the structural formula.
When compound A is treated with sodium methoxide, a substitution reaction predominates.
That means sodium methoxide is a strong base and a strong nucleophile.
But when it reacts with primary alkyl halides it forms a substitution product and when it reacts with secondary alkyl halide it forms mostly elimination product.
The reaction and the structures of A and B are shown below:
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Answer: The concentration of hydrochloric acid in the final solution is 0.72 M
Explanation:
According to the dilution law,
where,
= molarity of stock solution = 3.95 M
= volume of stock solution = 268 ml
= molarity of diluted solution = ?
= volume of diluted solution = 803 ml
Next, you take 100.00 ml of that solution and dilute it to 184 ml in a volumetric flask.
According to the dilution law,
where,
= molarity of stock solution = 1.32 M
= volume of stock solution = 100 ml
= molarity of diluted solution = ?
= volume of diluted solution = 184 ml
Thus concentration of hydrochloric acid in the final solution is 0.72 M