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ella [17]
2 years ago
8

How much energy is required to convert 400 g of ice at 0 °C to liquid water at 0 °C?

Chemistry
1 answer:
Tatiana [17]2 years ago
6 0

Answer:

133.20 kJ

Explanation:

The heat of fusion for water is  3.33 x 10^5 J/kg.

(400g)*(1 kg/1000g)*(3.33 x 10^5 J/kg) = 133200 J, or 133.20 kJ for 400g

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HELP PLSSSS
den301095 [7]

Answer:

Groups like the Halogens, which include Chlorine and Flourine, share similar properties both behaviorally and structurally. The Periodic Table is essentially a bunch of patterns and trends and the groups (like the one with Sodium and Potassium) were grouped together because of these similarities.

Explanation:

https://en.wikipedia.org/wiki/Alkali_metal

8 0
2 years ago
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xenn [34]

Answer:

Its C hope it helped

Explanation:

3 0
2 years ago
Chemistry an atom of strontium has at least four different isotopes. what is different between an isotope of 86sr and an isotope
lions [1.4K]
Isotopes are atoms of the same element that differ in the number of neutrons.

Remember that all the atoms of an element have the same number of protons. So the only difference between isotopes of an element is the number of neutrons.

86 Sr means that the mass number of this isotope is 86. Also, remember that the mass number is the number of protons plus the number of neutrons.

87 Sr means that the mass number of this isotope is 87.

So, 86 Sr and 87 Sr differ 1 neutron.

Answer: 1 neutron


5 0
2 years ago
What is meant by conversion of energy
MissTica

the process of changing one form of energy into another

4 0
3 years ago
If 3.53 g of CuNO, is dissolved in water to make a 0.330 M solution, what is the volume of the solution in milliliters?
solmaris [256]

Answer:

84.8 mL

Explanation:

From the question given above, the following data were obtained:

Mass of CuNO₃ = 3.53 g

Molarity of CuNO₃ = 0.330 M

Volume of solution =?

Next, we shall determine the number of mole in 3.53 g of CuNO₃. This can be obtained as follow:

Mass of CuNO₃ = 3.53 g

Molar mass of CuNO₃ = 63.5 + 14 + (16×3)

= 63.5 + 14 + 48

= 125.5 g/mol

Mole of CuNO₃ =?

Mole = mass / Molar mass

Mole of CuNO₃ = 3.53 / 125.5

Mole of CuNO₃ = 0.028 moles

Next, we shall determine the volume of the solution. This can be obtained as follow:

Molarity of CuNO₃ = 0.330 M

Mole of CuNO₃ = 0.028 moles

Volume of solution =?

Molarity = mole /Volume

0.330 = 0.028 / Volume

Cross multiply

0.330 × Volume = 0.028

Divide both side by 0.330

Volume = 0.028 / 0.330

Volume = 0.0848 L

Finally, we shall convert 0.0848 L to millilitres (mL). This can be obtained as follow:

1 L = 1000 mL

Therefore,

0.0848 L = 0.0848 L × 1000 mL / 1 L

0.0848 L = 84.8 mL

Therefore, the volume of the solution is 84.8 mL.

8 0
2 years ago
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