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Alenkinab [10]
3 years ago
7

New York State is located in which two hemispheres? How do you know this?

Chemistry
1 answer:
Helen [10]3 years ago
3 0
Well, every location is located in two hemispheres. New York is in the north western hemisphere. North of the equator and west of the prime meridian
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0.1gmin-1

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mass = 0.5g

time = 5minutes

rate= mass/time = 0.1gmin-1

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Please help me due tomorrow
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6 0
3 years ago
Which of the following will result in a chemical change?
Elis [28]
The correct answer is C.

Burning is a chemical change. It's a chemical process that includes oxygen.

All the other options are a change of state: form solid to liquid, or from liquid to  gas (as in the last one).
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Why is electromagnetic radiation a transverse wave?
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Since the direction of particle displacement in electromagnetic waves is also perpendicular to the direction of motion, generating the waveform of visible light and other forms of electromagnetic radiation, they are also transverse waves.

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How far a particle has moved from its original starting position, or, in the case of an ocean wave, how high or low the water is, is measured by its displacement or amplitude.

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6 0
1 year ago
The element iridium exists in nature as two isotopes: 191Ir has a mass of 190.9606 u, and 193Ir has a mass of 192.9629 u. The av
nlexa [21]

<u>Answer:</u> The percentage abundance of _{77}^{191}\textrm{Ir} and _{77}^{193}\textrm{Ir} isotopes are 37.10% and 62.90% respectively.

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i   .....(1)

Let the fractional abundance of _{77}^{191}\textrm{Ir} isotope be 'x'. So, fractional abundance of _{77}^{193}\textrm{Ir} isotope will be '1 - x'

  • <u>For _{77}^{191}\textrm{Ir} isotope:</u>

Mass of _{77}^{191}\textrm{Ir} isotope = 190.9606 amu

Fractional abundance of _{77}^{191}\textrm{Ir} isotope = x

  • <u>For _{77}^{193}\textrm{Ir} isotope:</u>

Mass of _{77}^{193}\textrm{Ir} isotope = 192.9629 amu

Fractional abundance of _{77}^{193}\textrm{Ir} isotope = 1 - x

Average atomic mass of iridium = 192.22 amu

Putting values in equation 1, we get:

192.22=[(190.9606\times x)+(192.9629\times (1-x))]\\\\x=0.3710

Percentage abundance of _{77}^{191}\textrm{Ir} isotope = 0.3710\times 100=37.10\%

Percentage abundance of _{77}^{193}\textrm{Ir} isotope = (1-0.3710)=0.6290\times 100=62.90\%

Hence, the percentage abundance of _{77}^{191}\textrm{Ir} and _{77}^{193}\textrm{Ir} isotopes are 37.10% and 62.90% respectively.

8 0
3 years ago
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