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2 years ago

New York State is located in which two hemispheres? How do you know this?

1 answer:

3 0

Well, every location is located in two hemispheres. New York is in the north western hemisphere. North of the equator and west of the prime meridian

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Which energy source uses a fuel that produces a large amount of energy from a small amount of fuel

Vitek1552 [10]

That would be either, nuclear power or wind power, depending on what the teacher is looking for...

8 0

2 years ago

What is the molarity of a solution containing 5 moles of HCl in 2.5 L of solution? Be sure to include the formula for calculatin

beks73 [17]

Answer:

$\boxed{\text{2 mol/L}}$

Step-by-step explanation:

$c = \dfrac{ \text{moles} }{ \text{litres}}\\\\c = \dfrac{n }{V }$

Data:

n = 5 mol

V = 2.5 L

Calculation:

$c = \dfrac{ \text{5 mol} }{\text{2.5 L}} = \text{2 mol/L}$

The molar concentration of the solution is $\boxed{\textbf{2 mol/L}}$ .

6 0

2 years ago

1. A 50 gram sample of a radioisotope decays to 12.5 grams in 14.4 seconds. What is

stiv31 [10]

Answer:

Half life = 7.2 seconds

Explanation:

$from \: decay \: equation \\ 2.303 log( \frac{n.}{nt} ) = kt \\ 2.303 log( \frac{50}{12.5} ) = k \times 14.4 \\ k = \frac{2.303 log( \frac{50}{12.5} )}{14.4} \\ k = 0.096288 {s}^{ - 1} \\ since \: half \: life = \frac{ ln(2) }{k} \\ half \: life = \frac{ ln(2) }{0.096288} \\ half \: life = 7.2 \: seconds$

5 0

2 years ago

Read 2 more answers

The change in entropy, Δ S ∘ rxn , is related to the the change in the number of moles of gas molecules, Δ n gas . Determine the

rewona [7]

Answer:

The entropy decreases.

Explanation:

The change in the standard entropy of a reaction (ΔS°rxn) is related to the change in the number of gaseous moles (Δngas), where

Δngas = n(gaseous products) - n(gaseous reactants)

If Δngas > 0, the entropy increases
If Δngas < 0, the entropy decreases.
If Δngas = 0, there is little or no change in the entropy.

Let's consider the following reaction.

2 H₂(g) + O₂(g) ⟶ 2 H₂O(l)

Δngas = 0 - 3 = -3, so the entropy decreases.

8 0

3 years ago

Why does water (H2O) have a significantly higher boiling point than methane (CH4)? Hydrogen forms a stronger covalent bond with

alexira [117]

The attraction of inter-molecular forces between molecules is defined by a general term "Van der Waals forces". It is the weak interactions caused by momentary changes in electron density in a molecule.

Inter-molecular forces that are present between hydrogen atom which is bonded to highly electronegative atom ( $F, O, and N$ ) and the lone pair electrons present in the other molecule on these electronegative atoms is known as hydrogen bonding.

The type of interactions between methane, $CH_4$ is Van der Waals interactions whereas in water, $H_2O$ is hydrogen bonding.

Since, the hydrogen bond is stronger than the Van der Waals forces so, it results in higher strength between the molecule possessing hydrogen bonding. Thus, molecules possessing hydrogen bonds will have higher boiling point than the molecules which possess Van der Waals forces.

Hence, water ( $H_2O$ ) have a significantly higher boiling point than methane ( $CH_4$ ) because water molecules are attracted to one another by hydrogen bonds.

3 0

3 years ago