Answer:
Procedure (2)
Explanation:
Assume the dialyses come to equilibrium in the allotted times.
Procedure (1)
If you are dialyzing 5 mL of sample against 4 L of water, the concentration of NaCl will be decreased by a factor of

Procedure (2)
For the first dialysis, the factor is

After a second dialysis, the original concentration of NaCl will be reduced by a factor of

Procedure (2) is more efficient by a factor of

Answer:
In conduction, heat transfer takes place between objects by direct contact. In convection, the heat transfer takes within the fluid. In radiation, heat transfer occurs through electromagnetic waves without involving particles. The heat transfer takes place due to the difference in temperature.
major conflict. Ellen continually suffers abuse by her neglectful caretakers and searches for a stable home and loving family. rising action. Ellen is placed in a number of temporary homes, all of which are unhappy, and she longs for a home where she is loved and cared for.
Answer:
0.3229 M HBr(aq)
0.08436M H₂SO₄(aq)
Explanation:
<em>Stu Dent has finished his titration, and he comes to you for help with the calculations. He tells you that 20.00 mL of unknown concentration HBr(aq) required 18.45 mL of 0.3500 M NaOH(aq) to neutralize it, to the point where thymol blue indicator changed from pale yellow to very pale blue. Calculate the concentration (molarity) of Stu's HBr(aq) sample.</em>
<em />
Let's consider the balanced equation for the reaction between HBr(aq) and NaOH(aq).
NaOH(aq) + HBr(aq) ⇄ NaBr(aq) + H₂O(l)
When the neutralization is complete, all the HBr present reacts with NaOH in a 1:1 molar ratio.

<em>Kemmi Major also does a titration. She measures 25.00 mL of unknown concentration H₂SO₄(aq) and titrates it with 0.1000 M NaOH(aq). When she has added 42.18 mL of the base, her phenolphthalein indicator turns light pink. What is the concentration (molarity) of Kemmi's H₂SO₄(aq) sample?</em>
<em />
Let's consider the balanced equation for the reaction between H₂SO₄(aq) and NaOH(aq).
2 NaOH(aq) + H₂SO₄(aq) ⇄ Na₂SO₄(aq) + 2 H₂O(l)
When the neutralization is complete, all the H₂SO₄ present reacts with NaOH in a 1:2 molar ratio.

Molecular weight of m is 40g. Hence, name of element m is Calcium. which is represented by the symbol Ca.
Given,
Moles of metal M = 0.300 moles
weight of mF₂ formed =23.4g
we have to find the name of element m...
Now,
m + F₂ → mF₂
1 mole of m reacts with 1 mole of F₂ (or 2 molecule of flourine) to form 1 mole of mF₂
Hence,
0.300 moles of m reacts with 0.300 moles of F₂ to form 0.300 moles of mF₂.
Hence,
23.4 g = 0.300 moles of mf2
0.300 × 38g + 0.300 × m = 23.4 g
Hence
m = 40 g
So, molecular weight of m is 40g. Hence, name of element m is Calcium. which is represented by the symbol Ca.
Thus, from the above conclusion we can say that, name of element m is Calcium. which is represented by the symbol Ca.
Learn more about Calcium here:brainly.com/question/26636816
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