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AnnZ [28]
4 years ago
14

Which of the following scenarios representsthe smallest percent change?​

Mathematics
1 answer:
mestny [16]4 years ago
8 0

Answer:

A baby that weighed 6 1/4 pounds at birth now weighs 8 pounds.

Step-by-step explanation:

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Olin [163]
94.2 in would be your answer
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3 years ago
1 unit by 2 units by<br> units
Julli [10]

Answer:

2

Step-by-step explanation:

1 unit by 2 unit means area.

So, know that in area you multiply length times width, you multiply 2 and 1.

1·2

Which is 2

8 0
3 years ago
A pen company averages 1.2 defective pens per carton produced (200 pens). The number of defects per carton is Poisson distribute
nlexa [21]

Answer:

a. P(x = 0 | λ = 1.2) = 0.301

b. P(x ≥ 8 | λ = 1.2) = 0.000

c. P(x > 5 | λ = 1.2) = 0.002

Step-by-step explanation:

If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

P(k)=\frac{\lambda^{k}e^{-\lambda}}{k!}= \frac{1.2^{k}\cdot e^{-1.2}}{k!}

a. What is the probability of selecting a carton and finding no defective pens?

This happens for k=0, so the probability is:

P(0)=\frac{1.2^{0}\cdot e^{-1.2}}{0!}=e^{-1.2}=0.301

b. What is the probability of finding eight or more defective pens in a carton?

This can be calculated as one minus the probablity of having 7 or less defective pens.

P(k\geq8)=1-P(k

P(0)=1.2^{0} \cdot e^{-1.2}/0!=1*0.3012/1=0.301\\\\P(1)=1.2^{1} \cdot e^{-1.2}/1!=1*0.3012/1=0.361\\\\P(2)=1.2^{2} \cdot e^{-1.2}/2!=1*0.3012/2=0.217\\\\P(3)=1.2^{3} \cdot e^{-1.2}/3!=2*0.3012/6=0.087\\\\P(4)=1.2^{4} \cdot e^{-1.2}/4!=2*0.3012/24=0.026\\\\P(5)=1.2^{5} \cdot e^{-1.2}/5!=2*0.3012/120=0.006\\\\P(6)=1.2^{6} \cdot e^{-1.2}/6!=3*0.3012/720=0.001\\\\P(7)=1.2^{7} \cdot e^{-1.2}/7!=4*0.3012/5040=0\\\\

P(k

c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?

We can calculate this as we did the previous question, but for k=5.

P(k>5)=1-P(k\leq5)=1-\sum_{k=0}^5P(k)\\\\P(k>5)=1-(0.301+0.361+0.217+0.087+0.026+0.006)\\\\P(k>5)=1-0.998=0.002

5 0
4 years ago
12. A flat, square roof needs a square patch in the corner to seal a leak. The side length of
NISA [10]

Answer:

Step-by-step explanation:

Area of the good part= area of whole roof - area of bad part

Since the roof is a square roof, the area will be calculated using the formulae for area of a square

Area of a square =length²

Area of good part =(x+12)²-x²

A= {(x+12)(x+12)} - x²

A = (x²+12x+12x+144) -x²

Open the bracket and rearrange the equation

A= x²-x²+24x+144

A=(24x+144) ft

5 0
3 years ago
Please help me I need this answer and I can not figure it out im not smart so could you please help
Rom4ik [11]

So really all you have to do is simply the expressions on top to match them.

Starting with (4t-8/5)-(3-4/3t), distribute the negative sign to the right portion in parentheses, then distribute it all out and you will get 16/3t- 23/5

Basically, use distribution to simplify, here's all the matches:

(4t-8/5)-(3-4/3t) --> 16/3t- 23/5

5(2t+1)+(-7t+28) --> 3t+33

(-9/2t+3)+(7/4t+33) --> -11/4t+36

3(3t-4)-(2t+10) --> 7t-22

6 0
3 years ago
Read 2 more answers
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