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Anna007 [38]
3 years ago
11

Someone pls explain how to do this-

Mathematics
2 answers:
andriy [413]3 years ago
7 0

Answer:

6 is wrong

Step-by-step explanation:

frosja888 [35]3 years ago
5 0

Answer:

3,6,6,9  (6 is not a function and has been repeated twice)

-1,-2,-5,-7  

sorry if their wrong id.rk

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What is the slope of the line with endpoints at (-3, 6) and (5.-6)?
podryga [215]

Answer:

-3/2

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-6-6)/(5-(-3))

m=-12/(5+3)

m=-12/8

simplify

m=-3/2

3 0
3 years ago
-3/8 - 7/8 = <br>explicar el procedimiento por favor ​
pogonyaev

Answer:

-1/4

Step-by-step explanation:

-3/8 - 7/8= 4/8=1/2

4 0
3 years ago
Write seven million six hundred twenty thousand six hundred fifty in standard form?​
Novay_Z [31]

Answer:

7,620,650

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
A student walk 60m on a bearing
Katena32 [7]

Answer:

d = 234.6 m

Step-by-step explanation:

You can consider a system of coordinates with its origin at the beginning of the walk of the student.

When she start to walk, she is at (0,0)m. After her first walk, her coordinates are calculated by using the information about the incline and the distance that she traveled:

x_1=60cos28\°=52.97m\\\\y_1=60sin28\°=28.16m

she is at the coordinates (52.97 , 28.16)m.

Next, when she walks 180m to the east, her coordinates are:

(52.97+180 , 28.16)m = (232.97 , 28.16)m

To calculate the distance from the final point of the student to the starting point you use the Pythagoras generalization for the distance between two points:

d=\sqrt{(x-x_o)^2+(y-y_o)^2}\\\\x=232.97\\\\x_o=0\\\\y=28.16\\\\y_o=0\\\\d=\sqrt{(232.97-0)^2+(28.16-0)^2}m=234.6m

The displacement of the student on her complete trajectory was of 234.6m

8 0
3 years ago
HELP ME FIND THE MEASURE OF THE ACUTE ANGLE !!!
tankabanditka [31]
Answer
55 for the top left and 35 for the top right
Explanation
7*7+6=49+6=55
And it is 7x+6

Top right
6x-7
6*7-7=42-7=35

6 0
3 years ago
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