Question

I need help on C......

Answer 1

Step-by-step explanation:

$B=100e^{0.592t}$

c) To solve for t, take the natural logarithm of the above equation:

$\dfrac{B}{100}=e^{0.592t}$

$\Rightarrow \ln \left(\dfrac{B}{100} \right) = \ln e^{(0.592t)}=(0.592t)\ln e$

Recall that $\ln e = 1$ so we can rewrite the equation above as

$0.592t = \ln \left(\dfrac{B}{100} \right)$

Finally, solving for t, we get

$t = \frac{1}{0.592} \ln \left(\dfrac{B}{100} \right)$