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Tju [1.3M]
3 years ago
13

What is the distance between (6, -2) and (3, -9)?

Mathematics
1 answer:
SVEN [57.7K]3 years ago
7 0
6 - 3 = 3 -2 - (-9) = 7 (3 , 7)
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Rectangle A' B' C' D' is the image of rectangle ABCD after a Dilation.
Svet_ta [14]

Answer:

Step-by-step explanations is the answer:

6 0
3 years ago
Segment AB has point A located at (6, 6). If the distance from A to B is 5 units, which of the following is the coordinate for p
Ierofanga [76]
The choices are (3, 2) (2, 5) (6, 7) and (7, 5). The distance formula given two points is d = square root of [<span>(y2−y1)^2+(x2−x1)^2]. In this case, we try every point in the choices and substitute y1 equal to 6 and x1 equal to 6 as well.  The answer is A from the choices. 
</span>d=square root of [(6−2)^2+(6−3)2]
d=square root of [(4)^2+(3)^2] d=square root of [16+9] d=<span>square root of [</span>25]
d=5
4 0
4 years ago
Over 30 points please help me i need it bad
pashok25 [27]
Distance formula: d= square root of (x2-x1)^2+(y2-y1)^2
(3,5) (7,3)
d= square root of (7-3)^2+(3-5)^2
d= square root of (4^2)+(-2^2)
d= square root of 16+4
d= square root of 20
d=4.47...rounded= 4.5
Hope this helped!
6 0
3 years ago
Let sin t = a, cos t = b, and tan t = c. Write the following expression in terms of a, b, and c.
Ira Lisetskai [31]
We use the trigonometric identities in this problem.

=(sin(t)cos(4π)+sin(4π)cos(t))−(cos(t)cos(8π)−sin(t)sin(8π)) +<span>tan(t)+tan(5π)/1−tan(t)tan(5π)
=</span>sin(t)+0−cos(t)+0+ tan(t)1−0<span>=sin(t)−cos(t)+tan(t)
=</span>a−b+c
8 0
3 years ago
Parallelogram<br> b=12 cm, h=10 cm, a=
Anna35 [415]
Answer: 120 cm^2

Step-by-Step Explanation:

Base (b) = 12 cm
Height (h) = 10 cm
Area (a) = bh

Therefore,
= bh
= b * h
= 12 * 10
=> 120

Area (a) = 120 cm^2
5 0
2 years ago
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