Formula y-y1= m(X-X1)
Since its parallel the m is 1/2
The -6 is X1 and the 4 is y1
Okay now do formula
Y-4= 1/2(X--6)
Y-4= 1/2X+3
Add 4
Y= 1/2x +7
Answer: -7
Step-by-step explanation:
-3x - 5 = 16 (add 5 to 16)
-3x = 21 (divide by -3)
x = -7
So the first two questions are asking for points of intercept. a is asking where the function crosses the x, in this case it is where y=0. So your x intercept is at x= 1,5. Then to find the y intercept it is where x=0, so just substitute 0 for x. Then you get your y intercept as y=5. Because your coefficient for the quadratic function is positive your function has a minimum since it opens upward. I’m not sure what is means by C coordinate, but your vertex is at (3,-4) and lime of symmetry is at x=3.
X intercepts: (1,0) and (5,0)
Y intercept: (0,5)
Answer:
The PERIMETER P is the distance around the rectangle.
Let's call the width of the rectangle W and the length of the rectangle L.
As you go around the edge there two equal lengths and two equal widths.
The formula for the perimeter of a rectangle is P=2*L+2*W.
P=2L%2B2W
Substitute 290 for P and 62 for the width.
290=2L%2B2%2862%29
Solve for L.
290=2L%2B2%2862%29
290=2L%2B124
290-124=2L
2L=166
L=83
The equation L=83 means that the length is 83 cm.
CHECK your work.
2(62)+2(83) = 124+166 = 290cm.
The length of the rectangle is 83cm.
PART A:
Find the rate of change between 1980 and 1989
d for P₁ = 80 - 60
d for P₁ = 20
d for P₂ = 76 - 82
d for P₂ = -6
The rate of change in P₁ is 20 hundred per year. The rate of change in P₂ is -6 hundred per year.
PART B:
Find the rate of change between 1989 and 1996
d for P₁ = 100 - 80
d for P₁ = 20
d for P₂ = 70 - 76
d for P₂ = -6
The rate of change in P₁ is 20 hundred per year. The rate of change in P₂ is -6 hundred per year.
PART C:
Find the rate of change between 1980 and 1996
d for P₁ = 100 - 60
d for P₁ = 40
d for P₂ = 70 - 82
d for P₂ = -12
The rate of change in P₁ is 40 hundred per year. The rate of change in P₂ is -12 hundred per year.
