Answer:
The equation has zero solutions because the equation 2 = 3 is never true.
Hope it helps :)
Answer:
a) 
b) 
c) 
d) 
Step-by-step explanation:
For each container, there are only two possible outcomes. Either it is undefilled, or it is not. This means that we can solve this problem using the binomial probability distribution.
Binomial probability distribution:
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinatios of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
In this problem
There are 10 containers, so
.
A food-packaging apparatus underfills 10% of the containers, so
.
a) This is P(X = 1)

b) This is P(X = 3)

c) This is P(X = 9)

d) This is
.
Either the number is lesser than five, or it is five or larger. The sum of the probabilities of each event is decimal 1. So:


In which







So

Finally

Answer:
Each Friend will get
cards.
Step-by-step explanation:
Let the number of cards be x.
Given:
Amount Nicole used to spend on cards = $9
Total cost of one set =$27
Also, she finds friends with the same amount of money to split the cost of a set.
So, Number of friends she finds can be calculated by dividing the Cost of 1 set with amount of money Nichole used to spend on cards.
Number of friends she finds = 
Hence she finds 2 friends and 1 is nichole hence there are 3 persons carrying $9 to buy $27 set of card
Now, Number of cards each friend gets is equal to Total number of Cards in 1 set divided by number of people.
Number of cards each friend = 
Hence Each Friend will get
cards.