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stiks02 [169]
3 years ago
12

Xion drives for 6 hours at 45 mph. How far does he travel? (Unit rate problem)

Mathematics
2 answers:
Oxana [17]3 years ago
7 0
270 hope this solves your question np
Ahat [919]3 years ago
6 0
If he goes 45 miles EACH hour then to solve multiply 45 by 6

45 x 6 = 270 miles
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The table below represents a linear function.
ohaa [14]
(-1,5)(1,9)
slope = (9 - 5) / (1 - (-1) = 4 / (1 + 1) = 4/2 = 2

y = mx + b
slope(m) = 2
use any of ur points in the table....(1,9)...x = 1 and y = 9
now we sub ad find b, the y int
9 = 2(1) + b
9 = 2 + b
9 - 2 = b
7 = b

so ur equation of the table is : y = 2x + 7.....where the slope = 2 and the y intercept = 7

so, the equation with the greater slope and the greater y int is :
y = 3x + 7.5....this has a slope of 3 and a y int of 7.5


8 0
3 years ago
What’s is the gcf 33c,55cd
Juli2301 [7.4K]
The GCF of 33c and 55cd is

33c/11c = 3
55cd/11c = 5d

the greatest common factor is 11c 

hope this helps
4 0
3 years ago
Find the coordinates of the point (x,y,z) on the planez=4x+3y+1 which is closest to the origin.
Nataliya [291]
Given plane Π : f(x,y,z) = 4x+3y-z = -1
Need to find point P on Π  that is closest to the origin O=(0,0,0).

Solution:
First step: check if O is on the plane Π : f(0,0,0)=0 ≠ -1 => O is not on Π
Next:
We know that the required point must lie on the normal vector <4,3,-1> passing through the origin, i.e. 
P=(0,0,0)+k<4,3,-1> = (4k,3k,-k)
For P to lie on plane &Pi; , it must satisfy
4(4k)+3(3k)-(-k)=-1
Solving for k
k=-1/26
=>
Point P is (4k,3k,-k) = (-4/26, -3/26, 1/26) = (-2/13, -3/26, 1/26)
because P is on the normal vector originating from the origin, and it satisfies the equation of plane &Pi;
Answer: P(-2/13, -3/26, 1/26) is the point on &Pi; closest to the origin.

8 0
3 years ago
What is the result when x^3-2x^2+5x-13x 3 −2x 2 +5x−13 is divided by x-2x−2?
Aleksandr [31]

yo k se wey: rg`weaofjwafgEWF3WRF1QTFG3Q2TGF2

3 0
3 years ago
Find the number of elements in A1 ∪A2 ∪A3 if there are 100 elements in A1, 1000 in A2, and 10,000 in A3 if a) A1 ⊆ A2 and A2 ⊆ A
Stella [2.4K]

Answer:

Step-by-step explanation:

Given that there are 3 sets such that  there are 100 elements in A1, 1000 in A2, and 10,000 in A3

a) If A1 ⊆ A2 and A2 ⊆ A3

then union will contain the same number of elements as that of A3

i.e. n(A1 ∪A2 ∪A3)=n(A3) =10000

b) If the sets are pairwise disjoint.

union will contain the sum of elements of each set

n(A1 ∪A2 ∪A3) = 100+1000+10000=11100

c) If there are two elements common to each pair of sets and one element in all three sets

We subtract common elements pairwise and add common element in 3

i.e. n(A1 ∪A2 ∪A3) = 100+1000+10000-2-2-2+1\\= 10995

5 0
3 years ago
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