Answer:
she had 16
16
She got c
16 + c
She now has 32
16 + c = 32
I don't know if that's the exact answer, but basically, 16 needs to be added to c, and it needs to equal 32.
Hope this helps! :)
5 1/2 * 3 1/4
1 + 5 . 2/2 * 1 + 3 . 4/4 = 11/2 * 13/4 = 11 . 13/2 . 4 = 143/8 = 7 + 17 . 8/8 = 17 7/8
= 17 . 875
Detailed explanation of solution:
5 1/2 * 3 1/4
Transform the first mix number to improper fraction:
5 1/2 = 1 + 5 . 2/2 = 11/2
Transform the second mix number to improper fraction:
3 1/4 = 1 + 3. 4/4 = 13/4
Multiplying two fractions:
11/2 * 13/4 = 11 . 13/2 . 4 = 143/8
Since the numerator is greater than the denominator, We convert the improper fraction to mix fraction:
143/8 = 7 + 17.8/8
= 17 7/8 (Decimal: 17. 875)
Hope that helps!!!!!! ( Answer: 17 7/8, (Decimal: 17.875)
Answer:
Step-by-step explanation:The solution is x > 3
There is an example hope it helped
Prime factors are factors of a composite number that are indivisible except by the number 1 or the number itself. The answers to your questions are the following:
1. Yes, it is possible especially for very large numbers.
2&3. No, because as mentioned previously, the default prime factors of numbers are 1 and the number itself. For example, 2 is a prime number. Its factors are 1 and 2.
4. Prime factorization are useful in fields of encryption. They make use of the basic prime numbers for the arithmetic modulus with the general equation: n=pq.
