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emmainna [20.7K]

2 years ago

13

From a boat on the lake, the angle of elevation to the top of a cliff is 27°57'. If the base of the cliff is 128 feet from the b

oat, how high is the cliff (to the nearest foot)?

1 answer:

Len [333]2 years ago

3 0

Here is your genuine answer

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PLEASE SHOW YOUR WORK!!! (solve system of equations by adding, subtracting, or multiplying.)

Aliun [14]

Hey friend, hope I can assist you!
I will solve by elimination <3.
Multiply 3x - 7y = 2 by 2: 6x - 14y = 4
6x - 14y = 4
6x - 9y = 9
5y = 5
Now we have
6x - 14y = 4
5y = 5
Now we want to solve 5y = 5 for y
So simply divide both sides by 5.
5y/5 = 5/5
This gives us one or in other words, y = 1.
Now we want to plug y = 1 into 6x - 14y = 4
So 6x - 14 * 1 = 4
This gives us
6x - 14 = 4
Now add 14 to both sides.
6x - 14 + 14 = 4 + 14
6x = 18
Now divide both sides by 6
6x/6 = 18/6
This gives us 3 so x = 3
Therefore our solutions to this system of equations would be y = 1 and x = 3

5 0

3 years ago

Which equation should be used to calculate the 43rd partial sum for the arithmetic sequence.

MariettaO [177]

Answer: First Option : Sₙ= n/2(a₁ + aₙ)

Step-by-step explanation:

The nth partial sum of an arithmetic sequence or the sum of the first n terms of the arithmetic series can be defined as the sum of a finite number of term in an arithmetic sequence.

It is calculated using the formula:

Sₙ= n/2(a₁ + aₙ)

Where :

a₁ = First term

aₙ = last term

n = number of terms

6 0

2 years ago

Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)

vagabundo [1.1K]

Answer:

Considering the given equation $y = log_{3}x\\$

And the ordered pairs in the format $(x, y)$

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For $(\frac{1}{3}, a_{0} )$

$x=\frac{1}{3}$

$y=a_{0}$

$y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1$

So the ordered pair will be $(\frac{1}{3}, -1 )$

For $(1, a_{1} )$

$x=1$

$y=a_{1}$

$y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0$

So the ordered pair will be $(1, 0 )$

For $(3, a_{2} )$

$x=3$

$y=a_{2}$

$y = log_{3}x\\y = log_{3}3\\y = 1$

So the ordered pair will be $(3, 1 )$

For $(9, a_{3} )$

$x=9$

$y=a_{3}$

$y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2$

So the ordered pair will be $(9, 2 )$

For $(27, a_{4} )$

$x=27$

$y=a_{4}$

$y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3$

So the ordered pair will be $(27, 3 )$

For $(81, a_{5} )$

$x=81$

$y=a_{5}$

$y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4$

So the ordered pair will be $(81, 4 )$

4 0

3 years ago

Solve the equation for x.<br> 15 = -2x + 3

bekas [8.4K]

Answer:

<h2>x = -6</h2>

Step-by-step explanation:

$-2x+3=15\qquad\text{subtract 3 from both sides}\\\\-2x+3-3=15-3\\\\-2x=12\qquad\text{divide both sides by (-2)}\\\\\dfrac{-2x}{2}=\dfrac{12}{-2}\\\\x=-6$

6 0

3 years ago

Read 2 more answers

What makes the statement true? 7^-2=

Damm [24]

<span>What makes the statement true?</span>7^-2= 0.0204081633

8 0

3 years ago

Read 2 more answers