3x-12y = 5
-x+3y = 9
First step is to make the coefficient of either x or y same.
3x-12y = 5
(-x+3y = 9)3
3x-12y = 5
-3x+9y = 27
-4y = 32
y = -8
9514 1404 393
Answer:
(d) A = 14.28 in², P = 14.28 in
Step-by-step explanation:
The figure is wholly contained within a 4" square, which has an area of (4 in)² = 16 in², and a perimeter of 4(4 in) = 16 in. Since the figure is smaller in area and has a shorter perimeter (the top corners are rounded, not square), both answer values must be less than 16.
The only reasonable choice is the last choice: 14.28 in², 14.28 in.
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If you want to figure this out in detail, you have the area of a rectangle that is 2 in by 4 in, and the area of a semicircle of radius 2 in. The total area is ...
A = LW +1/2πr²
A = (2 in)(4 in) + 1/2(3.14)(2 in)² = 8 in² +6.28 in²
A = 14.28 in²
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The perimeter is half that of a 4" square, plus half that of a 4" circle.
P = 1/2(4(4 in) +π(4 in)) = (2 in)(4 +π) = 2(7.14) in
P = 14.28 in
Answer:
Yes
Step-by-step explanation:
It has a 45 degree angle
<h3>
Answer: Approximately 35.54 degrees</h3>
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Explanation:
With respect to reference angle x, the 5 is the opposite side, and the adjacent side is 7 units long.
We'll use the tangent ratio here
tan(angle) = opposite/adjacent
tan(x) = 5/7
x = arctan(5/7)
x = 35.5376777919743 approximately
x = 35.54
I rounded to two decimal places, but you can round however you need to or however your teacher instructs. Arctangent is the same as inverse tangent. Be sure that your calculator is in degree mode.
