Answer:
-68/7
Step-by-step explanation:
slope1 of Car 1 that pass (-5,-8) (2,7)
= (y1-y2)/(x1-x2)=(2-(-5))/(7-(-8))=7/15
Slope2 of car 2 that pass (5,1) (10,y)
slope 1 and slope2 are perpendicular =>slope 2 =-15/7
make slope2 y=(-15/7)x+b
for it pass(5,1) => 1=(-15/7)5+b =>b=82/7 => y=(-15/7)x+82/7
put (10,y) in => y=(-15/7) 10+82/7=-68/7
Answer:
= 9x^15/7
Step-by-step explanation:
It should be D, I did the math :)
I think its the... second.... please correct me if im wrong :(
Answer:
5 or 6
Step-by-step explanation:
So I did it in a different way than shown in rsm classes. I said that the speed was x-2 and x.
then I said the distance was 6 and 15. If the time taken was 1 hour more, then we can come up with this equation:
Since the time is 6/x-2 or 15/x
15/x-6/x-2=1
multiply everything to get a common denominator then cancel it out to get
(15x-30)-6x=x^2-2x
11x-30=x^2
x^2-11x+30=0
(x-5)(x-6) is factored form.
so x=5 or x=6. this means that the speed of the boat is either 5km/h or 6 km/h
