Let (3,-2) be a point on the terminal side of theta in standard position. Find exact values of the six trigonometric functions o
f theta
1 answer:
Answer:
- sin(θ) = (-2√13)/13
- cos(θ) = (3√13)/13
- tan(θ) = -2/3
- sec(θ) = (√13)/3
- csc(θ) = (-√13)/2
- cot(θ) = -3/2
Step-by-step explanation:
The distance of the point from the origin is ...
r = √(3² +(-2)²) = √13
We know that ...
x = r·cos(θ) ⇒ cos(θ) = x/r = 3/√13 = (3√13)/13
y = r·sin(θ) ⇒ sin(θ) = y/r = -2/√13 = (-2√13)/13
tan(θ) = sin(θ)/cos(θ) = -2/3
sec(θ) = 1/cos(θ) = (√13)/3
csc(θ) = 1/sin(θ) = (-√13)/2
cot(θ) = 1/tan(θ) = -3/2
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