All categories

2 years ago

8 Vanesa wants to find the volume

Mathematics

2 answers:

gogolik [260]2 years ago

5 0

Answer:

Cubic inches. Think how small a lunchbox is

Step-by-step explanation:

deff fn [24]2 years ago

3 0

Cubic inches. Think how small a lunchbox is.

You might be interested in

(-3.5x + 1.7) + (9.1x - 0.3)=

yuradex [85]

Answer:

5.6x+1.4

Step-by-step explanation:

(-3.5x+1.7)+(9.1x-0.3)=-3.5x+9.1x+1.7-0.3=5.6x+1.4

7 0

3 years ago

The function f(x) =4x+3 represents the length of a rectangle. The function g(x)=2x-5 represents the width of the rectangle.Use (

nata0808 [166]

Answer: 32x-68

Step-by-step explanation:

(f•g) is equal to f(gx)

f(x)=4(2x-5)+3

Which is 8x-20+3=8x-17

Now multiply by 4.

4(8x-17)

= 32x-68

6 0

3 years ago

Read 2 more answers

Students have 40 minuets to complete 50 questions on the aspire ___ test

Murljashka [212]

I believe the answer to this is C. English.

3 0

3 years ago

Read 2 more answers

Which number line shows the solution of 4x - 36 < -12?

attashe74 [19]

the scanner will help u have u tried it yet

6 0

3 years ago

Write the equation of a polynomial of degree 3, with zeros 1, 2 and -1 where f(0)=2

drek231 [11]

<u>Answer:</u>

The equation of a polynomial of degree 3, with zeros 1, 2 and -1 is $x^{3}-2 x^{2}-x+2=0$

<u>Solution:</u>

Given, the polynomial has degree 3 and roots as 1, 2, and -1. And f(0) = 2.

We have to find the equation of the above polynomial.

We know that, general equation of 3rd degree polynomial is

$F(x)=x^{3}-(a+b+c) x^{2}+(a b+b c+a c) x-a b c=0$

where a, b, c are roots of the polynomial.

Here in our problem, a = 1, b = 2, c = -1.

Substitute the above values in f(x)

$F(x)=x^{3}-(1+2+(-1)) x^{2}+(1 \times 2+2(-1)+1(-1)) x-1 \times 2 \times(-1)=0$

$\begin{array}{l}{\rightarrow x^{3}-(3-1) x^{2}+(2-2-1) x-(-2)=0} \\ {\rightarrow x^{3}-(2) x^{2}+(-1) x-(-2)=0} \\ {\rightarrow x^{3}-2 x^{2}-x+2=0}\end{array}$

So, the equation is $x^{3}-2 x^{2}-x+2=0$

Let us put x = 0 in f(x) to check whether our answer is correct or not.

$\mathrm{F}(0) \rightarrow 0^{3}-2(0)^{2}-0+2=2$

Hence, the equation of the polynomial is $x^{3}-2 x^{2}-x+2=0$

3 0

3 years ago