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dybincka [34]
3 years ago
5

Can someone help me with these 2

Mathematics
1 answer:
frosja888 [35]3 years ago
4 0

Answer:

Step-by-step Yes it is, assuming we decide to use the Pythagorean Theorem to find the hypotenuse (10) it'll be possible considering the formula is c²=√a²+b²

(c being the longest side of the triangle)

a= 6 and b= 8

c² =√6² + 8²

c² = √100 square root of 100 equals 10

c= 10p explanation:

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Step-by-step explanation:

The x coordinate would be (-16,-8) I have had this question before hope it helps! ;)

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how many ways can 8 members of a family be seated side-by side in a movie theater if the father is seated on the aisle?
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I'm confused. Can someone help?
VARVARA [1.3K]

a.

The polynomial w^2+18w+84 cannot be factored

The perfect square trinomial is w^2+18w + 81

----------

The reason the original can't be factored is that solving w^2+18w+84=0 leads to no real solutions. Use the quadratic formula to see this. The graph of y = x^2+18x+84 shows there are no x intercepts. A solution and an x intercept are basically the same. The x intercept visually represents the solution.

w^2+18w+81 factors to (w+9)^2 which is the same as (w+9)(w+9). We can note that w^2+18w+81 is in the form a^2+2ab+b^2 with a = w and b = 9

================================================

b.

The polynomial y^2-10y+23 cannot be factored

The perfect square trinomial is y^2-10y + 25

---------

Using the quadratic formula, y^2-10y+23 = 0 has no rational solutions. The two irrational solutions mean that we can't factor over the rationals. Put another way, there are no two whole numbers such that they multiply to 23 and add to -10 at the same time.

If we want to complete the square for y^2-10y, we take half of the -10 to get -5, then square this to get 25. Therefore, y^2-10y+25 is a perfect square and it factors to (y-5)^2 or (y-5)(y-5)

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