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Flura [38]
3 years ago
15

Help please chapter 7.1

Chemistry
1 answer:
olga2289 [7]3 years ago
8 0
1. 100N to the right
2. 10N to the left
3. 0N they are balanced
4. 0N they are balanced
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Calculate the rate of dissolution (dM/dt) of relatively hydrophobic drug particles with a surface area of 2.5×103 cm2 and satura
Crank

Answer:

\large \boxed{\text{1.22 mg/s}}

Explanation:

We can use the Noyes-Whitney equation to calculate the rate of dissolution.

\dfrac{\text{d}M}{\text{d}t} = \dfrac{DA(C_{s} - C)}{d}

Data:

D = 1.75 × 10⁻⁷ cm²s⁻¹

A = 2.5 × 10³ cm²

Cₛ = 0.35 mg/mL

C = 2.1 × 10⁻⁴ mg/mL

d = 1.25 µm

Calculations:

Cₛ - C = (0.35 - 2.1 × 10⁻⁴) mg·cm⁻³ = 0.350 mg·cm⁻³

d = 1.25 µm = 1.25 × 10⁻⁶ m = 1.25 × 10⁻⁴ cm

\dfrac{\text{d}M}{\text{d}t} = \dfrac{(1.75 \times 10^{-7} \text{cm}^{2}\text{s}^{-1})(2.5 \times 10^{3} \text{ cm}^{2})(0.350\text{ mg$\cdot$cm$^{-3}$})}{1.25 \times 10^{-4} \text{ cm}} = \textbf{1.22 mg/s}\\\\\text{The rate of dissolution is $\large \boxed{\textbf{1.22 mg/s}}$}

8 0
3 years ago
Compute the value of the molar heat capacity at constant volume, CVCV, for CO2CO2 on the assumption that there is no vibrational
katovenus [111]

Answer:

Explanation:

Molar heat capacity at constant volume Cv  of a gas = n x .5 R where n is degree of freedom of the gas molecules

CO₂ is a linear molecule , so number of degree of freedom =  3 + 2 = 5

3 is translational and 2 is rotational degree of freedom . There is no vibrational degree of freedom given .

So Cv = 5 / 2 R

= 2.5 R .

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How many calories is 52 J of energy?
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1J = 0.238846cal

52J = 12.42cal

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3 years ago
How did the elements begin to stratify?
Bogdan [553]

Answer:

The process of elemental stratification relies on the diffusion velocity, which causes the migration of the different chemical elements within stars.

Explanation:

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3 years ago
3/4(x-2)=x-1 please answer me ​
Elan Coil [88]

Answer:

-2

Explanation:

3/2 (x-2) = x-1

<=> 3/4 x - 3/2 = x-1

<=> 3/4 x - x = 3/2 -1

<=> -1/4 x =1/2

<=> x= -2

3 0
3 years ago
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