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Ratling [72]
3 years ago
8

5(1-8r)+8r the awnser

Chemistry
2 answers:
andre [41]3 years ago
6 0
Just simplify 5-32r I believe :)
SashulF [63]3 years ago
5 0
=5(1-8r)+8r
distribute the 5 by all in parentheses

=(5*1) + (5*-8r) + 8r
= 5 - 40r + 8r
combine like terms

= 5 - 32r

Hope this helps! :)
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Which of the following individual actions would do the<br> most to reduce atmospheric methane?
Mekhanik [1.2K]

Answer:

oxygen

Explanation:

7 0
4 years ago
Given the following, what is the equilibrium constant for the reaction: 2 A + 3 D â 3 C + 2 B? I: 2 A â 2 B, K = 1x105 II: C â D
Anastasy [175]

Answer:

K= 1.25*10⁻⁵  (any of the options) , but if the problem's statement is wrong and D → C, K₂ =  [C]/[D] = 2*10³ then K= 8*10¹⁴ (option F)

Explanation:

for

2 A + 3 D → 3 C + 2 B

K= [C]³*[B]² /([A]²*[D]³) = ([B]/[A])²* ([C][/D])³

where

2 A → 2 B , K₁ = [B]²/[A]² = ([B]/[A])² =1*10⁵

and

C → D, K₂ =  [D]/[C] = 2*10³

therefore

K=K₁* (1/K₂)³=K₁/K₂³ = 1*10⁵ / (2*10³)³ = 1.25*10⁻⁵

K= 1.25*10⁻⁵

but if the problem's statement is wrong and

D → C, K₂ =  [C]/[D] = 2*10³

then

K=K₁*K₂³=K₁*K₂³ = 1*10⁵ * (2*10³)³ =8*10¹⁴

K= 8*10¹⁴

6 0
4 years ago
Metallic copper is formed when aluminum reacts with copper(ii) sulfate. how many grams of metallic copper can be obtained when 5
svetoff [14.1K]
Answer is: 127 <span>grams of metallic copper
</span>Chemical reaction: 2Al + 3CuSO₄ → Al₂(SO₄)₃ + 3Cu.
m(Al) = 54 g.
m(CuSO₄) = 319 g.
m(Cu) = ?
n(Al) = 54 g ÷ 27 g/mol
n(Al) = 2 mol.
n(CuSO₄) = 319 g ÷159,5 g/mol.
n(CuSO₄) = 2 mol, limiting reagens.
from reaction n(CuSO₄) : n(Cu) = 3 : 3 (1 : 1).
n(Cu) = 2 mol.
m(Cu) = 2 mol · 63,5 g/mol.
m(Cu) = 127 g.


6 0
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nasty-shy [4]

Answer:

yes

Explanation:

7 0
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Read 2 more answers
6.
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