The combustion of Methane produces CO₂ and water;
CH₄ + 2 O₂ → CO₂ + 2 H₂O
According to balance equation,
1 Mole of CH₄ on combustion give = 2 Moles of H₂O
So,
2 Moles of CH₄ will produce = X Moles of H₂O
Solving for X,
X = (2 Moles × 2 Moles) ÷ 1 Mole
X = 4 Moles
Result:
4 Moles of H₂O is produced on combustion of 2 Moles of CH₄.
Answer:
c. H2(g) + CuO(s) → Cu(s) + H2O(l)
e. H2(g) + Cl2(g) → 2HCl(g)
Explanation:
A redox reaction is a reaction that involves a changes in oxidation number of the species involved in the reaction.
The oxidizing agent experiences a decrease in oxidation number while the reducing agent experiences an increase in oxidation number.
For H2(g) + CuO(s) → Cu(s) + H2O(l)
Copper is reduced from +2 to 0 while hydrogen is oxidized from 0 to +2 Hence hydrogen is the reducing agent while copper is the oxidizing agent.
For H2(g) + Cl2(g) → 2HCl(g)
Chlorine is reduced from 0 to -1 while hydrogen is oxidized from 0 to +1. Hence chlorine is the oxidizing agent while hydrogen is the reducing agent.
Problem 2
You start out with 216 ugrams of Fermium - 253. After 3 days, you will have 1/2 as much. 108 ugrams is what you have.
Another 3 days goes by. You started with 108 ugrams. That gets cut in 1/2 again. Now you have 54 ugrams.
Finally another 3 days goes by. You started with 54 ugrams. you now have 1/2 as much which would be 27 ugrams
#days Amount in micrograms
0 216
3 108
6 54
9 27
Problem One
You are using Nitrogen as your base example. The first thing you should do is fill in the table. Then you should try and make some rules. You need the rules in case the exam you are preparing for picks a different element to talk about these bond tendencies. In any event, it's handy to think this way.
<em><u>Table</u></em>
Bond Energy Kj/Mol Bond Length pico meters
N - N 167 145
N=N 418 125
N≡N 942 110
<em><u>Rules</u></em>
As the number of bonds INCREASES, the energy contained in the bond goes UP
As the number of bonds INCREASES, the length of the bond goes DOWN.
Correct Answer: Mixture will be heterogeneous
Reason:
The mixture is said to be homogenous, if it contains single phase, On other hand, heterogenous system has, multiple phases. When, oil and vinegar are mixed together, on standing, the two liquids separates out as different phases. Hence, the mixture will be refereed as heterogeneous.
