Answer:
w= -9/8
Step-by-step explanation:
-1/3w -3/5 = 1/5w
+1/3w +1/3 w
-3/5=1/5w+1/3w
Make common denominators to combine like terms of the right
-3/5=1/5w+1/3w
*3 *5
-3/5=3/15w+5/15w
-3/5=8/15w
multiply both sides by the reciprocal of 8/15 which is 15/8
-3/5*15/8=8/15w*15/8
*
----> cross reduce 5 in the denominator becomes 1 and 15 in the numerator becomes 3
*
-----> now multiply across
w= -9/8
A quadrilatetal with two different pairs of equal and parallel sides.
I have attached a screenshot with the images of the two popcorn bags used by the theater.
Part (a):Bag A:Volume of bag = area of base * height
Volume of bag = length * width * height
We have:
volume = 96 in³
length = 3 in
width = 4 in
Therefore:
96 = 3 * 4 * height
96 = 12 * height
height of bag A = 8 inBag B:Volume of bag = area of base * height
Volume of bag = length * width * height
We have:
volume = 96 in³
length = 4 in
width = 4 in
Therefore:
96 = 4 * 4 * height
96 = 16 * height
height of bag B = 6 inPart (b):To determine the amount of paper needed, we will need to calculate the surface of each bag. Excluding the top base, each bag will have 5 faces. Four side faces (each two opposite are equal) and the base.
Bag A:Surface area = area of base + 2*area of front face + 2*area of side face
Surface area = (3*4) + 2(8*4) + 2(8*3)
Surface area = 12 + 64 + 48
Surface area of bag A = 124 in²Bag B:Surface area = area of base + 2*area of front face + 2*area of side face
Surface area = (4*4) + 2(6*4) + 2(6*4)
Surface area = 16 + 48 + 48
Surface area of bag B = 112 in²From the above calculations, we can deduce that
the theater should choose bag B in order to reduce the amount of paper needed.
Hope this helps :)
