Answer:
41.63g
Explanation:
Given parameters:
Volume of CaCl₂ = 500mL = 0.5L
Concentration = 0.75mol/L
Unknown:
Mass of the solute needed = ?
Solution:
The mass of the solute can be derived using the expression below;
Mass = number of moles x molar mass
But,
Number of moles = Concentration x Volume
So;
Mass = Concentration x Volume x molar mas
Molar mass of CaCl₂ = 40 + 2(35.5) = 111g/mol
Mass = 0.75 x 0.5 x 111 = 41.63g
Since the ethanol has a density of 0.800 g/mL, the mass of the ethanol is 180 grams.
<u>Given the following data:</u>
- Volume of ethanol = 225 mL
- Density of lead ball = 0.800 g/mL.
To find the mass of the ethanol;
Density can be defined as mass all over the volume of an object.
Mathematically, the density of a substance is given by the formula;

Making mass the subject of formula, we have;

Substituting the given parameters into the formula, we have;
<em>Mass of ethanol </em><em>=</em><em> 180 grams.</em>
Read more: brainly.com/question/18320053
<u>Answer:</u> The mass of water produced in the reaction is 97.2 grams
<u>Explanation:</u>
We are given:
Moles of calcium hydroxide = 2.70 moles
The chemical equation for the reaction of calcium hydroxide and HCl follows:

By Stoichiometry of the reaction:
1 mole of calcium hydroxide produces 2 moles of water
So, 2.70 moles of calcium hydroxide will produce =
of HCl
To calculate mass for given number of moles, we use the equation:
Molar mass of water = 18 g/mol
Moles of water = 5.40 moles
Putting values in above equation, we get:

Hence, the mass of water produced in the reaction is 97.2 grams
it is held every 4-5 years