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alex41 [277]
3 years ago
14

Under certain conditions the rate of this reaction is zero order in ammonia with a rate constant of ·0.0020Ms−1 : 2NH3 (g)→N2 (g

)+3H2 (g) Suppose a 5.0L flask is charged under these conditions with 500.mmol of ammonia. After how much time is there only 250.mmol left? You may assume no other reaction is important. Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits.
Chemistry
2 answers:
RSB [31]3 years ago
7 0

Answer:250

Explanation:

professor190 [17]3 years ago
5 0
The answer for this question is 250.
You might be interested in
6.0 mol Al reacts with 4.0 mol O2 to form Al2O3.
Tema [17]

Answer:

3.0 moles Al₂O₃

Explanation:

We do not know which of the reactants is the limiting reactant. Therefore, you need to convert both of the given mole values into the product. This can be done using the mole-to-mole ratio made up of the balanced equation coefficients.

4 Al + 3 O₂ -----> 2 Al₂O₃

6.0 moles Al            2 moles Al₂O₃
----------------------  x  -------------------------  =  3.0 moles Al₂O₃
                                    4 moles Al

4.0 moles O₂           2 moles Al₂O₃
----------------------  x  -------------------------  =  2.7 moles Al₂O₃
                                    3 moles O₂

As you can see, O₂ produces the smaller amount of product. This means O₂ is the limiting reactant. Remember, the limiting reactant is the reactant which runs out before the other reactant(s) are completely reacted. As such, the actual amount of Al₂O₃ produced is 2.7 moles.

However, since this problem is directly addressing how much Al₂O₃ is produced from Al, the answer you most likely are looking for is 3.0 moles Al₂O₃.

6 0
2 years ago
The following combinations are not allowed. If n and ml are correct, change the l value to create an allowable combination:
motikmotik

The allowable combination for the atomic orbital is n=3, l=1, m_{l}=-1.

<h3>What are the three quantum numbers of an atomic orbital?</h3>

Three quantum numbers specify an atomic orbital:

- The principal quantum number, n, which is a positive integer, describes the relative size of the orbital and its distance from the nucleus.

- l is the angular momentum quantum number that is related to the shape of the orbital; l is an integer from 0 to n-1 (so n limits l ),

- $\boldsymbol{m}_{l}$ is the magnetic quantum number that prescribes the three-dimensional shape of the orbital around the nucleus; m_{l} values are integers from -l to =l(l limits ml)

For n = 3, l can have three values: 0, 1, and 2. Since m_{l} values are integers from -l to 0 to +l, for l = 0 the value of m_{l} cannot be -1 (l = 0 has m_{l}= 0).

There are two l values that are consistent with n and m_{l} values:

l=1 or 2

Therefore, the allowable condition is n=3, l=1, m_{l}=-1.

To know more about quantum numbers, visit: brainly.com/question/16979660

#SPJ4

4 0
2 years ago
What is the chemical formula for the compound formed between sodium and iodine?
IrinaK [193]
Each compound will be neutral
6 0
3 years ago
If the density of mercury is 13.6 g/mL, what is the mass of 25.4 cm3 of<br> mercury?
Anettt [7]

Answer:

345.44 g or 0.34544 kg

Explanation:

Applying

D = m/V...................... Equation 1

Where D = Density of mercury, m = mass of mercury, V = Volume of mercury.

make m the subject of the equation

m = D×V................. Equation 2

From the question,

Given: D = 13.6 g/mL = 13.6 g/cm³, V = 25.4 cm³

Substitute these values into equation 2

m = 13.6×25.4

m = 345.44 g

m = 0.34544 kg

Hence the mass of mercury is 345.44 g or 0.34544 kg

4 0
3 years ago
Why is potassium permanganate, without any d electrons, bright purple in color?
velikii [3]
Cos purple is the end product of potassium
7 0
3 years ago
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