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2 years ago

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Describe how electrons move up and down energy levels (from ground state to an excited state, and vice versa).

1 answer:

Fittoniya [83]2 years ago

3 0

When elements are heated/energized their electrons then absorb the energy and transition into a higher energy level known as the excited state. Then electrons then eventually fall back to their lowest state of energy or their ground state.

hope this helps :)p

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When 0.50 L of a 12 M solution is diluted to 1.0 L, what is the resulting molarity?

Lyrx [107]

Answer:

The resulting molarity is 6M.

Explanation:

A dilution consists of the decrease of concentration of a substance in a solution (the higher the volume of the solvent, the lower the concentration).

We use the formula for dilutions:

C1 x V1 = C2 x V2

12 M x 0,5L = C2 x 1,0 L

C2= (12 M x 0,5 L)/1,0 L

<em>C2= 6 M</em>

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2 years ago

inn [45]

Answer:

маликулярная масса ровна 23

8 0

2 years ago

4.The scientific method is ________________ reasoning. You can make ______________ explanations for something that you are obser

Novay_Z [31]

Answer:

The scientific method is a system of reasoning. You can make reasonable explanations for something that you are observing in the world.

Explanation:

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2 years ago

2) Examine the molecules below.<br> Circle the molecules that can also be classified as compounds.

sergejj [24]

Answer:

3rd

Explanation:

its the way they look

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1 year ago

A quantity of 0.225 g of a metal M (molar mass = 27.0 g/mol) liberated 0.303 L of molecular hydrogen (measured at 17°C and 741 m

Lana71 [14]

Answer:

Oxide of M is $M_2O_3$ and sulfate of $M_2(SO_4)_3$

Explanation:

0.303 L of molecular hydrogen gas measured at 17°C and 741 mmHg.

Let moles of hydrogen gas be n.

Temperature of the gas ,T= 17°C =290 K

Pressure of the gas ,P= 741 mmHg= 0.9633 atm

Volume occupied by gas , V = 0.303 L

Using an ideal gas equation:

$PV=nRT$

$n=\frac{PV}{RT}=\frac{0.9633 atm\times 0.303 L}{0.0821 atm L/mol K\times 290 K}=0.01225 mol$

Moles of hydrogen gas produced = 0.01225 mol

$2M+2xHCl\rightarrow 2MCl_x+xH_2$

Moles of metal = $\frac{0.225 g}{27.0 g/mol}=8.3333 mol$

So, 8.3333 mol of metal M gives 0.01225 mol of hydrogen gas.

$\frac{8.3333}{0.01225 mol}=\frac{2}{x}$

x = 2.9 ≈ 3

$2M+6HCl\rightarrow 2MCl_3+3H_2$

$MCl_3\rightarrow M^{3+}+Cl^-$

Formulas for the oxide and sulfate of M will be:

Oxide of M is $M_2O_3$ and sulfate of $M_2(SO_4)_3$ .

3 0

2 years ago