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liberstina [14]
3 years ago
14

What is the pressure, in atmospheres, of 6.0 grams of H2 gas if it has a volume of 73 liters when the temperature is 25 C?

Chemistry
1 answer:
Archy [21]3 years ago
5 0
PV = nRT   (where P = pressure; V = volume; n = number of moles; R = gas constant; T = Temperature)

Moles of H₂ = mass of H₂ ÷ molar mass of H₂
                    =  6.0 g ÷ 2 g/mol
                    =  3.0 mol

To get the answer in atmospheres, let's convert C to K 
      25 °C ≡ 298 K

Now, based on the formula above
     P = (nRT) ÷ V

    P = (3.0 mol × (0.082 L · atm/mol · K) × 298 K) ÷  73 L
       ≈  1 .004 atm
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How much does one molecule of ethane (C2H6) weigh? anwser in units of g/molec.
Sladkaya [172]
30.07 g/mol (that’s grams per mole)
8 0
3 years ago
How many mL of a stock solution of 2.00 M KNO3 are needed to prepare 100.0 mL of 0.15M KNO3? with work plz
Tatiana [17]
Using the law of dilution :

Mi x Vi =  Mf x Vf

2.00 x Vi = 0.15 x 100.0

2.00 x Vi = 15

Vi = 15 / 2.00

Vi = 7.5 mL

hope this helps!


3 0
3 years ago
The average propane cylinder for a residential grill holds approximately 18 kg of propane. How much energy (in kJ) is released b
brilliants [131]
Combustion is a chemical reaction between a fuel and an oxidant, oxygen, to give off combustion products and heat. Complete combustion results when all of the fuel is consumed to form carbon dioxide and water, as in the case of a hydrocarbon fuel. Incomplete combustion results when insufficient oxygen reacts with the fuel, forming soot and carbon monoxide. 

The complete combustion of propane proceeds through the following reaction:
C_{3} H_{8} + 5O_{2} --> 3CO_{2} + 4H_{2}O

Combustion is an exothermic reaction, which means that it gives off heat as the reaction proceeds. For the complete combustion of propane, the heat of combustion is (-)2220 kJ/mole, where the minus sign indicates that the reaction is exothermic. 

The molar mass of propane is 44.1 grams/mole. Using this value, the number of moles propane to be burned can be determined from the mass of propane given. Afterwards, this number of moles is multiplied by the heat of combustion to give the total heat produced from the reaction of the given mass of propane.

 14.50 kg propane  x <u> 1000 g </u> x <u>  1 mole propane   </u>  x <u>  2220 kJ  </u>   
                                     1 kg              44.1 g                     1 mole

= 729,931.97 kJ
8 0
3 years ago
I NEED HELP ASAP PLEASE
scZoUnD [109]
I think it’d be C. I’m not 100% if it is tho
8 0
3 years ago
Science there’s a picture
melomori [17]

Answer:

D)

Explanation:

seems like the most logical option out of all listed.

4 0
2 years ago
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