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liberstina [14]
3 years ago
14

What is the pressure, in atmospheres, of 6.0 grams of H2 gas if it has a volume of 73 liters when the temperature is 25 C?

Chemistry
1 answer:
Archy [21]3 years ago
5 0
PV = nRT   (where P = pressure; V = volume; n = number of moles; R = gas constant; T = Temperature)

Moles of H₂ = mass of H₂ ÷ molar mass of H₂
                    =  6.0 g ÷ 2 g/mol
                    =  3.0 mol

To get the answer in atmospheres, let's convert C to K 
      25 °C ≡ 298 K

Now, based on the formula above
     P = (nRT) ÷ V

    P = (3.0 mol × (0.082 L · atm/mol · K) × 298 K) ÷  73 L
       ≈  1 .004 atm
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7 0
3 years ago
A sheet of gold weighing 8.8 g and at a temperature of 10.5°C is placed flat on a sheet of iron weighing 19.5 g and at a tempera
timofeeve [1]

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T = 36.393\,^{\textdegree}C

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The contact between the sheet of gold and the sheet of iron allows a heat transfer until thermal equilibrium is done, which means that both sheets have the same temperature:

-Q_{iron} = Q_{gold}

-(0.008\,kg)\cdot (452\,\frac{J}{kg\cdot ^{\textdegree}C} )\cdot (T-54.4\,^{\textdegree}C) = (0.0195\,kg)\cdot (129\,\frac{J}{kg\cdot ^{\textdegree}C} )\cdot (T-10.5\,^{\textdegree}C)

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-1.438\cdot (T - 54.4^{\textdegree}C) = T-10.5^{\textdegree}C

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