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MrRa [10]
3 years ago
12

Factorize: a^4+2xa³+a²x²-y^4

Mathematics
2 answers:
Art [367]3 years ago
5 0

9514 1404 393

Answer:

  (a^2 +ax -y^2)·(a^2 +ax +y^2)

Step-by-step explanation:

This can be factored as the difference of squares.

  a^4 +2a^3x +a^2x^2 - y^4 = a^2(a+x)^2 - y^4

  = (a(a+x) -y^2)(a(a+x) +y^2)

  = (a^2 +ax -y^2)·(a^2 +ax +y^2)

mart [117]3 years ago
4 0

Answer:

(a^2+ax-y) (a^2+ax+y^2)

Step-by-step explanation:

a^4+2xa³+a²x²-y^4

(a^2+ax)^2-y^4

(a^2+ax-y) (a^2+ax+y^2)

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I’m short word form 2,000,000+500,000+30,000+5,000+8
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Answer:

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4 0
2 years ago
What is 1/2(4x+14)=2(x-7)
GREYUIT [131]

Answer:

no solution

Step-by-step explanation:

1/2(4x+14)=2(x-7)

Multiply both sides by 2.

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Subtract 4x from both sides.

14 = -28

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Answer: no solution

8 0
3 years ago
How do I simplify the radical expression. √8-4√2
WITCHER [35]
√8 = √(4x2)  = 2√2

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3 0
3 years ago
I ONLY NEED HELP ON NUMBER 2
REY [17]
So, the area of a circle is a=pi r^2
so do that and get a=pi(4)
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4 0
2 years ago
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the\ period\ cosx\ is\ 2\pi\\\\the\ period\ 3cosx\ is\ 2\pi\\\\the\ period\ 3cos2x\ is\ 2\pi:2=\pi\leftarrow Answer
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