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MrRa [10]
3 years ago
12

Factorize: a^4+2xa³+a²x²-y^4

Mathematics
2 answers:
Art [367]3 years ago
5 0

9514 1404 393

Answer:

  (a^2 +ax -y^2)·(a^2 +ax +y^2)

Step-by-step explanation:

This can be factored as the difference of squares.

  a^4 +2a^3x +a^2x^2 - y^4 = a^2(a+x)^2 - y^4

  = (a(a+x) -y^2)(a(a+x) +y^2)

  = (a^2 +ax -y^2)·(a^2 +ax +y^2)

mart [117]3 years ago
4 0

Answer:

(a^2+ax-y) (a^2+ax+y^2)

Step-by-step explanation:

a^4+2xa³+a²x²-y^4

(a^2+ax)^2-y^4

(a^2+ax-y) (a^2+ax+y^2)

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If the domain of the coordinate transformation f(x,y)=(y+2,-x-4) is (1,-4),(3,-2), (0,-1)
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x (x, f(x)) f(x) g(x) = f(x)

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Step-by-step explanation:

8 0
3 years ago
How do you compute unit rates?
Ymorist [56]
You have to set them up as a proportion...
3 0
4 years ago
A(n) __________ equation is an equation that involves one or more absolute value expressions.
mestny [16]
J can give you some example: 
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8 0
3 years ago
ASAP!!! There are three marbles in a bag. One is red and two are black. What is the probability of picking a red marble first, p
DaniilM [7]

Answer:

The probability of picking a red marble first then replacing it and getting a black marble is 2/9. (The last option.)

Step-by-step explanation:

Hey there!

The probability of first getting a red marble is 1/3 since we have 1 red marble out of 2 + 1 = 3 total.

We put the marble back. The probability of then choosing a black marble is 2/3, since we have 2 black marbles out of 3 total.

So we get 1/3 * 2/3 = 2/9

The probability of picking a red marble first then replacing it and getting a black marble is 2/9. (The last option.)

Hope this helps, please mark brainliest if possible. Have a nice day. :)

8 0
3 years ago
Find the interest due on $1,090 at 8% for 5 years
Dafna11 [192]
Simple interest = PRT/100 = 1090 x 8 x 5 / 100 = $436
4 0
4 years ago
Read 2 more answers
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