Does anyone knows how to solve thiss
2 answers:
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Check the picture below.
is it even? well, even functions use the y-axis as a mirror, so a pre-image on the right-side, will be a mirror of the image on the left-side, but in this case it isn't so, if you put a mirror right on the y-axis, the left-side will look a bit different.
does it have a zero at x = 0? well, just look at the graph, is the line touching the x-axis at 0? nope.
does it have an asymptote at 0? well, surely you can see it right there.
is it even? well, even functions use the y-axis as a mirror, so a pre-image on the right-side, will be a mirror of the image on the left-side, but in this case it isn't so, if you put a mirror right on the y-axis, the left-side will look a bit different.
does it have a zero at x = 0? well, just look at the graph, is the line touching the x-axis at 0? nope.
does it have an asymptote at 0? well, surely you can see it right there.
Answer:
-
Step-by-step explanation:
-x= -1x. (The 1 is invisible)
Now lets do the 3*-1= -3
You still have both of the x's.
All you do is add them. 1+1=2
So, your exponent is going to be 2 with x attached
***When you are multiplying and you have the same exponent, add them. Pretend that you see the exponent 1 by the x () now since you have 2 (
) which equals (
)
Looks Like:
3x* -x
=3x* -(1)x
=
Hope this helped :)