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PilotLPTM [1.2K]
3 years ago
9

The graph below shows how the speed of a bus change during part of a journey. Use this graph to answer questions 3-5

Physics
2 answers:
Minchanka [31]3 years ago
6 0

Answer:

O to A and D to E are accelorating.

Explanation:

You can tell because the graphed points have positive slopes in these locations.

Bogdan [553]3 years ago
3 0

Answer:

since the line goes in between 12 and 14 the answer is 13

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Calculate the density of a sample of gas with a mass of 30 g and volume of 7500 cm3.
zepelin [54]

By definition we have that the density is given by:

D = \frac{M}{V}

Where,

M: mass of the sample

V: volume occupied by the sample

Therefore, substituting values in the given equation we have:

D = \frac{30}{7500}

D = 0.004 \frac{g}{cm^3}

Answer:

the density of a sample of gas with a mass of 30 g and a volume of 7500 cm3 is:

D = 0.004 \frac{g}{cm^3}

4 0
3 years ago
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What is the name given to group 18 on the periodic table?​
zhannawk [14.2K]

Answer:

Noble gases

also known as group 0

7 0
3 years ago
Each roller under a conveyor belt has a radius of 0.5 meters. the rollers turn at a rate of 30 revolutions per minute. what is t
svp [43]
Distance in a minute=<span>0.5 times 30=15 meters
distance in a second</span><span>=15 divided by 60=0.25 meters per second
hope it helps</span>
3 0
3 years ago
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what is the period of a sound wave whose wavelength is 20.0m? use values from the book and show all of your work
Lera25 [3.4K]
The wavelength of a sound wave is related to its frequency by the relationship:
f= \frac{v}{\lambda}
where
f is the frequency
v is the speed of the wave
\lambda is the wavelength

The wave in our problem has wavelength of \lambda=20.0 m and speed of v=343 m/s (this is the speed of sound in air), therefore its frequency is
f= \frac{343 m/s}{20.0 m}=17.15 Hz

And the period of the wave is equal to the reciprocal of its frequency:
T= \frac{1}{f}= \frac{1}{17.15 Hz}=0.058 s
5 0
4 years ago
A wheel in the shape of a flat, heavy, uniform, solid disk is initially at rest at the top of an inclined plane of height 2.00 m
olasank [31]

Answer:

Explanation:

If friction is neglected, the wheel cannot roll and can only slide frictionlessly and will have the same velocity at the bottom of the ramp as if it had been in free fall as it has converted the same amount of potential energy.

mgh = ½mv²

v = √(2gh) = √(2(9.81)(2.00)) = 6.26418... = 6.26 m/s

However if we do not ignore all friction and the wheel rolls without slipping down the slope, the potential energy becomes linear and rotational kinetic energy

mgh = ½mv² + ½Iω²

mgh = ½mv² + ½(½mR²)(v/R)²

2gh = v² + ½v²

2gh = 3v²/2

v = √(4gh/3) =√(4(9.81)(2.00)/3) = 5.11468... = 5.11 m/s

7 0
3 years ago
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