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natita [175]
3 years ago
14

What roles do exchange particles play in an interaction?

Physics
1 answer:
Vlad [161]3 years ago
5 0


The exchange particles you are talking about are probably the gauge bosons. They are elementary bosons, meaning that they are elementary particles making part of the standard model and they have integer spin. There are four of them: The photon, the gluon, the W+ and W- bosons and the Z boson. The photon basically is the particle of light being an excitation, if you will, of the electromagnetic field so that is mediates the electromagnetic force. The only thing that differs from long range photons (light) is that they are what is called virtual photons but that is for another subject. Then you have the gluons that come in 8 varieties and their role is to interchange the color charge in between quarks so that it mediates the strong nuclear force, the force that keeps quarks bounded into protons. And then finally there are the W+, W- and Z bosons that mediates this time, the weak nulear force, the force that allows protons to coexist in the nucleus of atoms with neutrons. I hope that helped you, but as i usually do, i tried to simplify my answer beacause i could have written a lot mor about that!


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The correct answer is:
<span>B.) At terminal velocity there is no net force 

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</span>\sum F = ma = 0
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8 0
3 years ago
The potential at location A is 382 V. A positively charged particle is released there from rest and arrives at location B with a
jarptica [38.1K]

Answer: 247.67 V

Explanation:

Given

Potential At A V_a=382\ V

Potential at V_c=785\ V

when particle starts from A it reaches with velocity v_b at Point while when it starts from C it reaches at point B with velocity 2v_b

Suppose m is the mass of Particle

Change in Kinetic Energy of particle moving under the Potential From A to B

q\cdot \left ( V_a-V_b\right )=0.5m\cdot (v_b)^2----1

Change in Kinetic Energy of particle moving under the Potential From C to B

q\cdot \left ( V_c-V_b\right )=0.5m\cdot (2v_b)^2-----2

Divide 1 and 2 we get

\frac{V_a-V_b}{V_c-V_b}=\frac{v_b^2}{4v_b^2}

on solving we get

V_b=\frac{4}{3}\cdot V_a-\frac{1}{3}\cdot V_c

V_b=\frac{743}{3}=247.67\ V

                     

4 0
3 years ago
What is the current when the voltage is 18 volts and the resistance is 6 ohms?
juin [17]
Voltage = current(I) * resistance (R)
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18 = I * 6
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Scilla [17]

Answer:

C. 0.2 Hertz

Explanation:

The frequency of a spring is equal to the reciprocal of the period:

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f is the frequency

T is the period

For the spring in this problem,

T = 5 s

therefore, the frequency is

f=\frac{1}{5 s}=0.2 Hz

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