The strength of an electric field depends on the
2 answers:
<span>The correct option is D) both A and B. In fact, the strength of an electric field produced by a single point charge is given by
</span>
<span>
where Q is the charge that generates the field, k is the Coulomb's constante and r is the distance from the charge source of the field.
From the equation, we see that the strength of the field depends on A) the amount of charge that produced the field (Q) and B) the distance from the charge (r), so the correct option is D.</span>
</span>
where Q is the charge that generates the field, k is the Coulomb's constante and r is the distance from the charge source of the field.
From the equation, we see that the strength of the field depends on A) the amount of charge that produced the field (Q) and B) the distance from the charge (r), so the correct option is D.</span>
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In a series circuit the total current is the same throughout resistors and so:
The voltage is distributed throughout the resistors and so:
and the total resistance can be calculated by adding up the resistors resistance:
First thing is to calculate the total resistance and so:
And by Omh's law V=IR we have:
And so the total current of the circuit is 1.2 amps i.e. 1.2 A.
Answer:
0.3659
Explanation:
The power (p) is given as:
P = AeσT⁴
where,
A =Area
e = transmittivity
σ = Stefan-boltzmann constant
T = Temperature
since both the bulbs radiate same power
P₁ = P₂
Where, 1 denotes the bulb 1
2 denotes the bulb 2
thus,
A₁e₁σT₁⁴ = A₂e₂σT₂⁴
Now e₁=e₂
⇒A₁T₁⁴ = A₂T₂⁴
or
substituting the values in the above question we get
or
=0.3659