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3 years ago

A 5.0-newton force could have perpendicular components of

Physics

1 answer:

tino4ka555 [31]3 years ago

7 0

Answer:

It can have many set of perpendicular component but the most important one is 3 AND 4

Explanation:

PLEASE MARK ME BRAINLIEST IF MY ANSWER IS CORRECT PLEASE 

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An upward force of 18 N is applied via a string to lift a ball with a mass of 1.5 kg.

valentinak56 [21]

net force = applied force + gravity = 18N+(1.5kg)(-9.8m/s^2) = 3.3N

Force=mass times acceleration
acceleration=Force/mass
acceleration=3.3/1.5 m/s^2
acceleration=2.2m/s^s

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3 years ago

A train is moving along a track with constant speed v1 relative to the ground. A person on the train holds a ball of mass m and

scoundrel [369]

Answer:

$(a)0.5m(2v1v2+v2^{2})\\(b)0.5m(v2^{2}-v1^{2})\\(c)0.5m(2v1v2+v2^{2})\\(d)0.5m(v2^{2}-v1^{2})$

Explanation:

velocity of ball in train reference = v2

velocity of ball in earth reference = v1+v2

(a)

Kinetic energy is given by $0.5mv^{2}$ where m and v are the mass and velocity of object respectively.

Change in kinetic energy is given by subtracting initial kinetic energy from the final kinetic energy. In this case

Initial kinetic energy= $0.5mv1^{2}$

Final kinetic energy= $0.5m (v1+v2)^{2}=0.5m(v1^{2}+2v1v2+v2^{2})$

Change in kinetic energy= $0.5m (v1+v2)^{2}-0.5mv1^{2}=0.5m((v1+v2)^{2})-v1^{2}=0.5m(2v1v2+v2^{2}$

(b)

Change in velocity in train reference will be

Initial kinetic energy= $0.5mv1^{2}$

Final kinetic energy= $0.5mv2^{2}$

Change in kinetic energy= $0.5m(v2^{2}-v1^{2})$

(c)

Work done, W = change in kinetic energy= $0.5m (v1+v2)^{2}-0.5mv1^{2}=0.5m((v1+v2)^{2})-v1^{2}=0.5m(2v1v2+v2^{2}$

(d)

Work done, W = change in kinetic energy= $0.5m(v2^{2}-v1^{2})$

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3 years ago

Is molten lava heterogeneous

zhenek [66]

Yes, considering lava accommodates rocks that have collapsed of cave walls it is heterogeneous.

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4 years ago

What information does the period number give about an atom?

Anton [14]

Answer:All of the elements in a period have the same number of atomic orbitals. For example, every element in the top row (the first period) has one orbital for its electrons. All of the elements in the second row (the second period) have two orbitals for their electrons.Explanation:

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