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Yuliya22 [10]
3 years ago
13

1.86 x 10 and 1.86 x 100. I need the solving steps please

Mathematics
1 answer:
AlekseyPX3 years ago
5 0

Answer: I don't know if this would be helpful, but in this case, you can really just move the decimal point to the right the amount of times you see a zero in what you are multiplying it by. 1.86 x 10 = 18.6 , 1.86 x 100 = 186

Step-by-step explanation:

Sorry if its not helpful im trying..

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A particular type of mouse's weights are normally distributed, with a mean of 359 grams and a standard deviation of 33 grams. If
igor_vitrenko [27]

Answer:

Following are the responses to the given points:

Step-by-step explanation:

Given:

\mu = 359 \ \ \ \ \ \sigma = 33\\\\

Using formula:

\to P(X = x) = P\left ( z < \frac{x-\mu }{\sigma } \right )

For point a:

\to x= 406\\\\P(X < 406 ) = P\left ( z < \frac{406-359 }{33 } \right )\\\\

                   = P\left ( z

For point b:

\to x= 461\\\\P(X > 461 ) = P\left ( z > \frac{461 -359 }{33 } \right )\\\\

                   = 1 - P\left ( z < 3.0909 \right )\\\\= 1 - 0.9990\\\\= 0.0001

For point c:

\to x= 406\ \ and \ \  461\\\\P(406

                              = 0.9990 - 0.9222\\\\= 0.0768\\\\

For point d:

P(X < 406) = 0.9222 = 92.22 \%\  that \ is \ greater \ than\ 50\%

Hence, the correct choice is "i".

For point e:

\to P(X > z) = 0.1\\\\\to 1 - P(X < z) = 0.1\\\\\to P(\frac{x-\mu }{\sigma }) = 0.9\\\\\to \frac{x-359}{33 } = 1.28\\\\ \to x = 401.24\\\\

5 0
3 years ago
A computer program has a bug that causes it to fail once in every thousand runs, on average. In an effort to find the bug, indep
Serhud [2]

Answer:

The standard deviation of the number of runs required is 2447.26

Step-by-step explanation:

For each run, there are only two possible outcomes. Either the program fails, or it does not. The probability of the computer failing during a run is independent of other runs. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The standard deviation for the expected number of trials for r sucesses is:

\sqrt{V(X)} = \sqrt{\frac{r(1-p)}{p^{2}}}

A computer program has a bug that causes it to fail once in every thousand runs, on average.

This means that p = \frac{1}{1000} = 0.001

In an effort to find the bug, independent runs of the program will be made until the program has failed six times. What is the standard deviation of the number of runs required?

This means that r = 6. So

\sqrt{V(X)} = \sqrt{\frac{6*0.999}{(0.001)^{2}}} = 2447.26

The standard deviation of the number of runs required is 2447.26

8 0
3 years ago
11+4(x+2y+4)<br> A) 4x+2y+27<br> B) 4x+8y+11<br> C) 4x+8y+27<br> D) 4x+8y+10
lesantik [10]

Answer:

The answer is C) 4x + 8y +27.

3 0
3 years ago
It costs $60 to reserve a movie theater for a party. There is also a charge of $3 for each person. Write an expression that repr
dimulka [17.4K]

Answer

Now I'm not the best at this so don't go with mine but i'm gonna say

the expression could be n x 3 + 60

Step-by-step explanation:

if n = 4 then multiply 3 x 4 = 12 then 12 + 60 = 72

I don't know sorry i tried

6 0
3 years ago
The sum of three consecutive even integers is –78. What are the integers?
Korvikt [17]

Answer:

the three even integers are -28, -26 and -24.

Step-by-step explanation:

Represent the three numbers as follows:

n

n+2

n+4

Their sum is n + n+2 + n+4 = -78.

Combining the n terms, we get:

3n + 6 = -78, or

3n = -84

Then n = -84/3, or n = -28.

Then the three even integers are -28, -26 and -24.

3 0
4 years ago
Read 2 more answers
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