1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lisov135 [29]
3 years ago
6

Help pleaseeeeeeeeee i dont know what else to write i just need 20 characters

Mathematics
1 answer:
Dmitrij [34]3 years ago
4 0

Answer:

the answer is...

Step-by-step explanation:

You might be interested in
Given the functions =−12 (2)x+3. Select all statements that are true.
Natali5045456 [20]
There ya go, the graphing

8 0
2 years ago
Solve for b. Express your answer as an integer or integers or in simplest radical form. -165= -3-6b^3
Fynjy0 [20]
I wanna help you but I don’t understand sorry
4 0
2 years ago
9. Gold miners in Alaska have found, on average, 12 ounces of gold per 1000 tons of dirt excavated with a standard deviation of
netineya [11]

Answer:

9.18% probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 12, \sigma = 3

What is the probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated?

This is 1 subtracted by the pvalue of Z when X = 16. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{16 - 12}{3}

Z = 1.33

Z = 1.33 has a pvalue of 0.9082

1 - 0.9082 = 0.0918

9.18% probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated

5 0
2 years ago
The endpoints of CD are C(3,−5) and D(7, 9).<br> The coordinates of the midpoint M of CD are?
Nutka1998 [239]

Answer:

M(5,2)

Step-by-step explanation:

We use the midpoint rule:

( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} )

We just have to find the arithmetic mean of the x and y-coordinates.

The endpoints of CD are given as C(3,−5) and D(7, 9).

We substitute these values to get:

( \frac{7 + 3}{2}, \frac{9 +  - 5}{2} )

( \frac{10}{2}, \frac{4}{2} )

(5, 2)

Therefore the coordinates of the midpoint M of CD are (5,2)

3 0
3 years ago
Manny has 48 feet of wood. He wants to use all of it to create a border around a garden. The equation 2 l plus 2 w equals 48 can
Lelu [443]

Answer:

2l + 2w = 48

if garden is 15' long

2(15) + 2w = 48 \\ 30 + 2w = 48 \\ 30 - 30 + 2w = 48 - 30 \\ 2w = 18 \\  \frac{2w}{2}  =  \frac{18}{2}  \\ w = 9 \: feet \: wide

7 0
3 years ago
Other questions:
  • One bag holds 12 bolts. Several bags filled with bolts are packed into a box and shipped to the factory. The box contains a tota
    11·2 answers
  • Help me please , i’m being timed and i’m so lost
    14·1 answer
  • Which statement is true?
    11·1 answer
  • The standard Olympic marathon distance is 26 miles 385 yards. What is this distance in kilometres to 3 decimal places? (1 yard ?
    5·1 answer
  • Plot the line for the the equation on the graph y-2=-2(x+4)
    11·1 answer
  • Which value for x makes the sentence true? 12x-5 = 5x + 23<br><br> A. 6<br> B. 9<br> C. 4 <br> D. -1
    5·1 answer
  • Hwllppooppppoopppppppp
    14·2 answers
  • What is the decimal multiplier to increase by 5.3%?​
    9·2 answers
  • - Which of the following expressions has a coefficient of 10 and a constant of 5?
    5·1 answer
  • The distance across a two lane road
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!