Answer:
The sum of this entire line is 180, so to solve this we would subtract 20 from 180, which means x = 160.
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Is RS perpendicular to DF? Select Yes or No for each statement. R (6, −2), S (−1, 8), D (−1, 11), and F (11 ,4) R (1, 3), S (4,7
guajiro [1.7K]
I'll do the first one to get you started.
Find the slope of the line between R (6,-2) and S (-1,8) to get
m = (y2-y1)/(x2-x1)
m = (8-(-2))/(-1-6)
m = (8+2)/(-1-6)
m = 10/(-7)
m = -10/7
The slope of line RS is -10/7
Next, we find the slope of line DF
m = (y2 - y1)/(x2 - x1)
m = (4-11)/(11-(-1))
m = (4-11)/(11+1)
m = -7/12
From here, we multiply the two slope values
(slope of RS)*(slope of DF) = (-10/7)*(-7/12)
(slope of RS)*(slope of DF) = (-10*(-7))/(7*12)
(slope of RS)*(slope of DF) = 10/12
(slope of RS)*(slope of DF) = 5/6
Because the result is not -1, this means we do not have perpendicular lines here. Any pair of perpendicular lines always has their slopes multiply to -1. This is assuming neither line is vertical.
I'll let you do the two other ones. Let me know what you get so I can check your work.
Pythagoras’ Theorem = a^2+b^2=c^2
c^2= 5^2+12^2
=25+144
=169
c= sqrt of 169
c=13
Hypotenuse=13cm
Answer:
Step-by-step explanation:
x+10=0
x=-10
so vertex is (-10,-105)
Answer:
I help u to find x
sln
<COE+ <AOE+ < DOA=180(because straight angle)
x+46+90=180
x+136=180
x=44
the angle ×=44
